zoukankan      html  css  js  c++  java
  • POJ2262Goldbach's Conjecture

    Description

    In 1742, Christian Goldbach, a German amateur mathematician, sent a letter to Leonhard Euler in which he made the following conjecture:
    Every even number greater than 4 can be
    written as the sum of two odd prime numbers.

    For example:
    8 = 3 + 5. Both 3 and 5 are odd prime numbers.
    20 = 3 + 17 = 7 + 13.
    42 = 5 + 37 = 11 + 31 = 13 + 29 = 19 + 23.

    Today it is still unproven whether the conjecture is right. (Oh wait, I have the proof of course, but it is too long to write it on the margin of this page.)
    Anyway, your task is now to verify Goldbach's conjecture for all even numbers less than a million.

    Input

    The input will contain one or more test cases.
    Each test case consists of one even integer n with 6 <= n < 1000000.
    Input will be terminated by a value of 0 for n.

    Output

    For each test case, print one line of the form n = a + b, where a and b are odd primes. Numbers and operators should be separated by exactly one blank like in the sample output below. If there is more than one pair of odd primes adding up to n, choose the pair where the difference b - a is maximized. If there is no such pair, print a line saying "Goldbach's conjecture is wrong."

    Sample Input

    8
    20
    42
    0
    

    Sample Output

    8 = 3 + 5
    20 = 3 + 17
    42 = 5 + 37
    

    CODE:

    View Code
     1 #include <iostream>
     2 #include <cstring>
     3 using namespace std;
     4 
     5 int isprime(int i)
     6 {
     7     for(int j=2; j*j<=i; j++)
     8     {
     9         //cout<<"j"<<endl;
    10         if(i%j==0)
    11         {
    12             //cout<<"out"<<endl;
    13             return 0;
    14         }
    15         //cout<<"j2"<<endl;
    16     }
    17 
    18     return 1;
    19 };
    20 
    21 int main()
    22 {
    23     int n;
    24 
    25     int i;
    26     while(cin>>n&&n)
    27     {
    28         i=2;
    29 
    30         for(i=2;i<=n/2;i++)
    31             if(isprime(i)&&isprime(n-i))
    32             {
    33                 cout<<n<<" = "<<i<<" + "<<n-i<<endl;
    34                 break;
    35             }
    36         if(i==(n/2 + 1))
    37         cout<<"Goldbach's conjecture is wrong."<<endl;
    38     }
    39     return 0;
    40 }



  • 相关阅读:
    【pygame游戏编程】第二篇-----移动图像
    【pygame游戏编程】第五篇-----动画显示
    【pygame游戏编程】第四篇-----打字测速游戏
    【pygame游戏编程】第一篇-----创建一个窗口
    pygame编程之font模块
    pygame编组(精灵组)Group中的常用方法介绍
    javascript遍历对象的属性
    Spring中的@ImportResource
    SpringBoot中的@ConfigurationProperties
    开源协议是什么?有哪些?如何选择?
  • 原文地址:https://www.cnblogs.com/panderen/p/2439602.html
Copyright © 2011-2022 走看看