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  • C++对象初始化以及运算符重载

    #include <iostream>
    using namespace std;
    
    class A{
    private:
    	int num;
    public:
        A(int num){
    		this->num = num;
    	}
    	
    	void printA(){
    		cout<<"A "<<num<<endl;
    	}
    };
    
    template <class T>
    class demostrate{
    public:
    	demostrate(T* pObj = 0){
    		cout<<"default constructor"<<endl;
    	};
    	demostrate(const demostrate &demo){
    		cout<<"copy constructor";
    	}
    	//demostrate(demostrate<T> demo){};
    	demostrate& operator=(T *t);
    };
    
    
    template <class T>
    demostrate<T>& demostrate<T>::operator=(T *t){
    	cout<<"operator overload"<<endl;
    	t->printA();
    	return *this;
    }
    
    class B{
    	
    public:
    	B(A* a){
    		a->printA();
    		cout<<"new A "<<endl;
    	}
    	
    	B(int bint){
    		cout<<"bint "<<bint<<endl;
    	}
    	
    	B(int a, int b, int c){
    		cout<<"output a,b,c "<<a<<b<<c<<endl;
    	}
    };
    
    int main(){
    	//第一种方法提示conversion from ‘A*’ to non-scalar type ‘demostrate<A>’ requested
    	//带有声明的对象初始化,实际上是调用构造函数,所以构造函数一定要有demostrate(T* pObj = 0)形参列表
    	demostrate<A> demo = new A(100);
    	
    	/*
    	//第二种方法调用的是运算符重载方法
    	demostrate<A> demo;
    	demo = new A(100);
    	
    	
    	B b= new A(200);
    	
    	B b2 = 300;
    	
    	B b3 = {100, 200, 300};
    	*/
    	return 0;
    }
    

    在C++中,为构造函数指定实参有三种等价形式:

           Account acct1("Anna Press");

           Account acct2 = Account("Anna Press");

           Account acct3 = "Anna Press";

           acct3的形式只能被用于指定单个实参的情形,对于两个以上的实参,只能使用acct1和acct2的形式,推荐acct1。

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  • 原文地址:https://www.cnblogs.com/peer/p/2107491.html
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