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  • 40. Combination Sum II

    Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T.

    Each number in C may only be used once in the combination.

    Note:

    • All numbers (including target) will be positive integers.
    • Elements in a combination (a1, a2, … , ak) must be in non-descending order. (ie, a1 ≤ a2 ≤ … ≤ ak).
    • The solution set must not contain duplicate combinations.

    For example, given candidate set 10,1,2,7,6,1,5 and target 8
    A solution set is: 
    [1, 7] 
    [1, 2, 5] 
    [2, 6] 
    [1, 1, 6] 

    也是比较经典的问题。然后就是注意同一个a[i]只能用1次。

    class Solution {
    public:
        void dfs(vector<int>& a,vector<vector<int> >&v,vector<int>&tmp,int x,int sum,int target){
            if(sum>target)return ;
            if(sum==target){
                v.push_back(tmp);
                return ;
            }
            for(int i=x;i<a.size();i++){
                if(sum+a[i]>target)break;
                if(i>x&&a[i]==a[i-1])continue;
                tmp.push_back(a[i]);
                dfs(a,v,tmp,i+1,sum+a[i],target);
                tmp.pop_back();
            }
        }
        vector<vector<int>> combinationSum2(vector<int>& candidates, int target) {
            sort(candidates.begin(),candidates.end());
            vector<vector<int> >v;
            vector<int>tmp;
            dfs(candidates,v,tmp,0,0,target);
            return v;
        }
    };
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  • 原文地址:https://www.cnblogs.com/pk28/p/5355741.html
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