zoukankan      html  css  js  c++  java
  • poj--2234--Matches Game(尼姆博弈)

    Time Limit: 1000MS   Memory Limit: 65536KB   64bit IO Format: %I64d & %I64u

    Status

    Description

    Here is a simple game. In this game, there are several piles of matches and two players. The two player play in turn. In each turn, one can choose a pile and take away arbitrary number of matches from the pile (Of course the number of matches, which is taken away, cannot be zero and cannot be larger than the number of matches in the chosen pile). If after a player’s turn, there is no match left, the player is the winner. Suppose that the two players are all very clear. Your job is to tell whether the player who plays first can win the game or not.

    Input

    The input consists of several lines, and in each line there is a test case. At the beginning of a line, there is an integer M (1 <= M <=20), which is the number of piles. Then comes M positive integers, which are not larger than 10000000. These M integers represent the number of matches in each pile.

    Output

    For each test case, output "Yes" in a single line, if the player who play first will win, otherwise output "No".

    Sample Input

    2 45 45
    3 3 6 9
    

    Sample Output

    No
    Yes
    

    Source

    POJ Monthly,readchild


    #include<stdio.h>
    #include<string.h>
    int main()
    {
    	int n,pre[10010];
    	while(scanf("%d",&n)!=EOF)
    	{
    		int re=0;
    		memset(pre,0,sizeof(pre));
    		for(int i=0;i<n;i++)
    		{
    			scanf("%d",&pre[i]);
    			re^=pre[i];
    		}
    		if(re) printf("Yes
    ");
    		else printf("No
    ");
    	}
    }


  • 相关阅读:
    Oracle 控制文件
    rm 删除文件
    FreeBSD 8.0候选版本RC3发布
    【非长篇大论】X3D Web3D标准的发展
    【短】又碰到CSDN服务器负载过重
    年终总结 等待
    项目管理软件InDefero
    X3D 与 HTML5
    对使用破解软件的一点想法
    Flash开发的基本概念
  • 原文地址:https://www.cnblogs.com/playboy307/p/5273776.html
Copyright © 2011-2022 走看看