zoukankan      html  css  js  c++  java
  • The Triangle--nyoj 18

    The Triangle

    时间限制:1000 ms  |  内存限制:65535 KB
    难度:4
    描述

    7
    3 8
    8 1 0
    2 7 4 4
    4 5 2 6 5
    (Figure 1)
    Figure 1 shows a number triangle. Write a program that calculates the highest sum of numbers passed on a route that starts at the top and ends somewhere on the base. Each step can go either diagonally down to the left or diagonally down to the right.

    输入
    Your program is to read from standard input. The first line contains one integer N: the number of rows in the triangle. The following N lines describe the data of the triangle. The number of rows in the triangle is > 1 but <= 100. The numbers in the triangle, all integers, are between 0 and 99.
    输出
    Your program is to write to standard output. The highest sum is written as an integer.
    样例输入
    5
    7
    3 8
    8 1 0 
    2 7 4 4
    4 5 2 6 5
    
    样例输出
    30



    其实就是一个简单的dp思想,每一步都去了最优值从而达到整体最优

    代码

    #include<stdio.h>
    #include<string.h>
    #include<algorithm>
    using namespace std;
    int a[1010][1010],i,j,n,sum;
    int main()
    {
    	memset(a,0,sizeof(a));
    	sum=0;
    	scanf("%d",&n);
    	for(i=1;i<=n;i++)
    	{
    		for(j=1;j<=i;j++)
    		scanf("%d",&a[i][j]);
    	}
    	for(i=n-1;i>=1;i--)
    	{
    		for(j=1;j<=i*2-1;j++)
    		{
    			a[i][j]=max(a[i][j]+a[i+1][j],a[i][j]+a[i+1][j+1]);
    		}
    	}
    	printf("%d
    ",a[1][1]);
    	return 0;
    } 



  • 相关阅读:
    软件工程第二次作业
    软件工程第一次作业
    细说GitHub分支策略和工作流
    第二次结对作业 四则运算生成器
    第一次结对作业
    软件工程第三次作业
    软件工程第二次作业
    软件工程第一次作业
    人工智能第一次作业
    人工智能第二次作业 书上69页作业
  • 原文地址:https://www.cnblogs.com/playboy307/p/5273809.html
Copyright © 2011-2022 走看看