zoukankan      html  css  js  c++  java
  • luogu2754 星际转移问题

    源向地球连
    月球向汇连
    每一天往下一天连
    飞船上一天与这一天连
    枚举答案

    #include <iostream>
    #include <cstring>
    #include <cstdio>
    #include <queue>
    using namespace std;
    struct Edge{
    	int too, nxt, val;
    }edge[1000005];
    int n, m, k, cnt, hea[10005], ans, lev[10005], maxFlow, r[25], l[25];
    int a[25][25], ss, tt;
    const int oo=0x3f3f3f3f;
    queue<int> d;
    void add_edge(int fro, int too, int val){
    	edge[cnt].nxt = hea[fro];
    	edge[cnt].too = too;
    	edge[cnt].val = val;
    	hea[fro] = cnt++;
    }
    void addEdge(int fro, int too, int val){
    	add_edge(fro, too, val);
    	add_edge(too, fro, 0);
    }
    bool bfs(){
    	memset(lev, 0, sizeof(lev));
    	d.push(ss);
    	lev[ss] = 1;
    	while(!d.empty()){
    		int x=d.front();
    		d.pop();
    		for(int i=hea[x]; i!=-1; i=edge[i].nxt){
    			int t=edge[i].too;
    			if(!lev[t] && edge[i].val>0){
    				lev[t] = lev[x] + 1;
    				d.push(t);
    			}
    		}
    	}
    	return lev[tt]!=0;
    }
    int dfs(int x, int lim){
    	if(x==tt)	return lim;
    	int addFlow=0;
    	for(int i=hea[x]; i!=-1 && addFlow<lim; i=edge[i].nxt){
    		int t=edge[i].too;
    		if(lev[t]==lev[x]+1 && edge[i].val>0){
    			int tmp=dfs(t, min(lim-addFlow, edge[i].val));
    			edge[i].val -= tmp;
    			edge[i^1].val += tmp;
    			addFlow += tmp;
    		}
    	}
    	return addFlow;
    }
    void dinic(){
    	while(bfs())	maxFlow += dfs(ss, oo);
    }
    int main(){
    	memset(hea, -1, sizeof(hea));
    	cin>>n>>m>>k;
    	for(int i=1; i<=m; i++){
    		scanf("%d %d", &r[i], &l[i]);
    		for(int j=0; j<l[i]; j++){
    			scanf("%d", &a[i][j]);
    			a[i][j] += 2;
    		}
    	}
    	n += 2;
    	ss = 0; tt = 9999;
    	while(ans<500){
    		addEdge(ss, ans*n+2, oo);
    		addEdge(ans*n+1, tt, oo);
    		if(ans){
    			for(int i=1; i<=n; i++)
    				addEdge((ans-1)*n+i, ans*n+i, oo);
    			for(int i=1; i<=m; i++){
    				int uu=a[i][(ans-1)%l[i]];
    				int vv=a[i][ans%l[i]];
    				addEdge((ans-1)*n+uu, ans*n+vv, r[i]);
    			}
    		}
    		dinic();
    		if(maxFlow>=k)	break;
    		ans++;
    	}
    	if(ans<500)	cout<<ans<<endl;
    	else	cout<<"0"<<endl;
    	return 0;
    }
    
  • 相关阅读:
    BZOJ2142: 礼物
    GYM100633J. Ceizenpok’s formula 扩展lucas模板
    Codeforces451E Devu and Flowers
    BZOJ2982: combination Lucas模板
    UVAL3700
    BZOJ2821: 作诗(Poetize)
    BZOJ2724: [Violet 6]蒲公英
    Luogu P1858 多人背包
    Luogu P2831 愤怒的小鸟(状压+记忆化搜索)
    Luogu P4205 [NOI2005]智慧珠游戏
  • 原文地址:https://www.cnblogs.com/poorpool/p/8116294.html
Copyright © 2011-2022 走看看