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  • javaWeb之写一个最简单的servlet

    1. 创建一个类servletTest2 继承HttpServlet类。

    public class servletTest2 extends HttpServlet {
    
        public servletTest2(){
            super();
        }
    
        @Override
        protected void doGet(HttpServletRequest req, HttpServletResponse resp)
                throws ServletException, IOException {
    
            resp.setContentType("text/html");
            PrintWriter out = resp.getWriter();
            out.println("<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">");
            out.println("<HTML>");
            out.println("  <HEAD><TITLE>A Servlet</TITLE></HEAD>");
            out.println("  <BODY>");
            out.print("    This is ");
            out.print(this.getClass());
            out.println(", using the GET method");
            out.println("  </BODY>");
            out.println("</HTML>");
            out.flush();
            out.close();
        }
        
    }

    web.xml中增加servlet的定义

      <servlet>
          <servlet-name>servletTest2</servlet-name>
          <servlet-class>servletTest2</servlet-class>
      </servlet>
      
      <servlet-mapping>
          <servlet-name>servletTest2</servlet-name>
          <url-pattern>/test</url-pattern>
      </servlet-mapping>

    例如项目名是test,运行tomcat,打开浏览器访问地址:http://127.0.0.1:8080/test/test

    显示如下:

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  • 原文地址:https://www.cnblogs.com/powerwu/p/7096342.html
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