hdu 1037 Keep on Truckin'

Keep on Truckin'

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 10764    Accepted Submission(s): 7462

Problem Description

Boudreaux and Thibodeaux are on the road again . . .

"Boudreaux, we have to get this shipment of mudbugs to Baton Rouge by tonight!"

"Don't worry, Thibodeaux, I already checked ahead. There are three underpasses and our 18-wheeler will fit through all of them, so just keep that motor running!"

"We're not going to make it, I say!"

So, which is it: will there be a very messy accident on Interstate 10, or is Thibodeaux just letting the sound of his own wheels drive him crazy?

 

Input

Input to this problem will consist of a single data set. The data set will be formatted according to the following description.

The data set will consist of a single line containing 3 numbers, separated by single spaces. Each number represents the height of a single underpass in inches. Each number will be between 0 and 300 inclusive.

 

Output

There will be exactly one line of output. This line will be:

   NO CRASH

if the height of the 18-wheeler is less than the height of each of the underpasses, or:

   CRASH X

otherwise, where X is the height of the first underpass in the data set that the 18-wheeler is unable to go under (which means its height is less than or equal to the height of the 18-wheeler).
The height of the 18-wheeler is 168 inches.

 

Sample Input

180 160 170

 

Sample Output

CRASH 160

 

Source

South Central USA 2003

 

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这题简直水到没朋友。。。看懂题意一定会做。

 

题意：输入三个数，如果小于等于168，则按题意输出，如果三个数都大于168，则输出 NO CRASH 。

 

附上代码：

 

#include <cstdio>
#include <iostream>
using namespace std;
int main()
{
    int a[5],i,k;
    while(~scanf("%d%d%d",&a[1],&a[2],&a[3]))
    {
        k=0;
        for(i=1; i<=3; i++)
            if(a[i]<=168)
            {
                printf("CRASH %d
",a[i]);
                k++;
            }
        if(k==0)
            printf("NO CRASH
");
    }
    return 0;

}