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  • python面试题&练习题之嵌套循环

    1、打印如下结果:

    1*5=5
    2*10=20
    3*15=45
    ...
    10*50=500
    
    for i in range(1,11):
        print(str(i)+'x'+str((i*5))+'='+str((i*i*5)))
    
    方法二:
    for a in range(1,11):
        b=a*5;
        print(a,"*",b,"=",a*b);

    2、本金10000元存入银行,年利率是千分之三,每过1年,将本金和利息相加作为新的本金。计算5年后,获得的本金是多少?

    money = 10000
    for i in range(5):
         sum_money = money + money * 0.003
    print(num1)

    3、计算1900年1月1日到今天(如:2019年12月20日)相距多少天。

    sum = 0;
    for year in range(1900,2019):
        if (year%4==0 and year%100!=0) or (year%400==0):
            sum = sum + 366;
        else:
            sum = sum + 365;
    
    for month in range(1,9):
        if month in [1,3,5,7,8,10,12]:
            sum = sum + 31;
        elif month in [4,6,9,11]:
            sum = sum + 30;
        else:
            if (2019% 4 == 0 and 2019 % 100 != 0) or (2019 % 400 == 0):
                sum = sum + 29;
            else:
                sum = sum + 28;
    
    print(sum-1);

    4、打印如下图案:
    *
    **
    ***
    ****
    *****

    for i in range(1,6):
        print('*'*i)

    5、打印如下图案:
    *
    ***
    *****
    *******
    *********

    for i in range(1,11,2):
        print('*'*i)

    6、打印如下图案:
    #####*
    ####***
    ###*****
    ##*******
    #*********

    for j in range(1,11,2):
        for i in range(1,11-j,2):
            print('#',end='')
        print('*'*j)
      

    7、打印如下图案:
        *
       ***
      *****
     *******
    *********
     *******
      *****
       ***
        *

    s = '*'
    for i in range(1,10,2):
        print((s*i).center(9))
    for i in reversed(range(1,8,2)):
        print((s*i).center(9))

    8、打印99乘法表

    for i in range(1,10):
        for j in range(1,i+1):
            print(str(j)+'x'+str(i)+'='+str(j*i),end=' ')
        print()

    9、定义一个List,任意输入10个数字保存到List,然后按从小到大排序。(冒泡排序)

    list1 = []
    for j in range(1,11):
        num = input('请输入10个数字,已输入第{}个数'.format(j))
        num = int(num)
        list1.append(num)
    len_sum = len(list1)
    for x in range(len_num-1):
        for y in range(len_num-1-x):
            if list1[y]>list1[y+1]:
                list1[y],list1[y+1]=list1[y+1],list1[y]
    print(list1)
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  • 原文地址:https://www.cnblogs.com/puti306/p/12080475.html
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