python调用c/c++时传递结构体参数

背景：使用python调用linux的动态库SO文件,并调用里边的c函数，向里边传递结构体参数。直接上代码

//test1.c


# include <stdio.h>
# include <stdlib.h>

//创建一个Student结构体 
struct Student
{
    char name[30];
    float fScore[3];
};

void Display(struct Student su)
{
    printf("-----Information------\n");
    printf("Name:%s\n",su.name);
    printf("Chinese:%.2f\n",su.fScore[0]);
    printf("Math:%.2f\n",su.fScore[1]);
    printf("English:%.2f\n",su.fScore[2]);
    printf("总分数为:%f\n", su.fScore[0]+su.fScore[1]+su.fScore[2]);
    printf("平均分数为:%.2f\n",((su.fScore[0]+su.fScore[1]+su.fScore[2]))/3);
}

生成libpycall.so文件：

gcc -o libpycall.so -shared -fPIC test1.c

python调用，给Display传递结构体参数：

#pycall.py

import ctypes
from ctypes import *

class Student(Structure):
    _fields_ = [("name",c_char * 30),
            ("fScore", c_float * 3)
            ]    

su = Student()
su.name = b"test-sdk"
PARAM = c_float * 3
fScore = PARAM()
fScore[0] = 55.1
fScore[1] = 33.2
fScore[2] = 51.3

su.fScore = fScore

if __name__ == '__main__':
    
    ll = ctypes.cdll.LoadLibrary   
    lib = ll("./libpycall.so") 
    # lib.Display.restype = c_float
    lib.Display.argtypes = [Student]   #这一行很重要 
    lib.Display(su)  
    print('----- finish -----') 

输出Display函数调用结果：

-----Information------
Name:test-sdk
Chinese:55.10
Math:33.20
English:51.30
总分数为:139.600006
平均分数为:46.53
----- finish -----