RSA--通过模和指数加密模板--无填充

一.模板一

import rsa
#模
m = "ae068c2039bd2d82a529883f273cf20a48e0b6faa564e740402375a9cb332a029b8492ae342893d9c9d53d94d3ab8ae95de9607c2e03dd46cebe211532810b73cc764995ee61ef435437bcddb3f4a52fca66246dbdf2566dd85fbc4930c548e7033c2bcc825b038e8dd4b3553690e0c438bbd5ade6f5a476b1cbc1612f5d501f"
#指数
e = '10001'
#加密参数
message = '123456'

class Encrypt(object):
    def __init__(self, e, m):
        self.e = e
        self.m = m

    def encrypt(self, message):
        mm = int(self.m, 16)
        ee = int(self.e, 16)
        rsa_pubkey = rsa.PublicKey(mm, ee)
        crypto = self._encrypt(message.encode(), rsa_pubkey)
        return crypto.hex()

    def _pad_for_encryption(self, message, target_length):
        message = message[::-1]
        max_msglength = target_length - 11
        msglength = len(message)

        padding = b''
        padding_length = target_length - msglength - 3

        for i in range(padding_length):
            padding += b'x00'

        return b''.join([b'x00x00', padding, b'x00', message])

    def _encrypt(self, message, pub_key):
        keylength = rsa.common.byte_size(pub_key.n)
        padded = self._pad_for_encryption(message, keylength)

        payload = rsa.transform.bytes2int(padded)
        encrypted = rsa.core.encrypt_int(payload, pub_key.e, pub_key.n)
        block = rsa.transform.int2bytes(encrypted, keylength)

        return block

if __name__ == '__main__':
    en = Encrypt(e, m)
    print(en.encrypt(message))

二.模板二

import codecs

def rsa_encrypt(content):
    public_exponent = '010001'
    public_modulus = 'ae068c2039bd2d82a529883f273cf20a48e0b6faa564e740402375a9cb332a029b8492ae342893d9c9d53d94d3ab8ae95de9607c2e03dd46cebe211532810b73cc764995ee61ef435437bcddb3f4a52fca66246dbdf2566dd85fbc4930c548e7033c2bcc825b038e8dd4b3553690e0c438bbd5ade6f5a476b1cbc1612f5d501f'

    content = content[::-1]
    rsa = int(codecs.encode(content.encode('utf-8'), 'hex_codec'),
              16) ** int(public_exponent, 16) % int(public_modulus, 16)
    # 把10进制数rsa转为16进制（'x'表示16进制），再取前256位，不够的在最前面补0
    return format(rsa, 'x').zfill(256)

三.模板三

import math
if __name__ == '__main__':
    # 实为16进制串，前补0
    e = ''
    # m也需要补00
    m = '008eb933413be3234dddd2730fbb1d05c8848a43d5dc3bdd997f2a9935fba6beb9ffb36854482b0b46cf7e6f9afbbe2e2e7d606fde20bec57dbf722e7985192e8813e6b67628a6f202cf655b7d2ffce4e9dc682dd6034ae706c8e255f25e4051b9ca43f25b3ad686aac9c8f6aeb71d921c13a255c806f78a5a7b9a356c2dd274e3'
    m = int.from_bytes(bytearray.fromhex(m), byteorder='big')
    e = int.from_bytes(bytearray.fromhex(e), byteorder='big')
    # js加密为反向，为保持一致原文应反向处理，所以这里原文实际为204dowls
    plaintext = 'slwod402'.encode('utf-8')
    # 无填充加密逻辑
    input_nr = int.from_bytes(plaintext, byteorder='big')
    crypted_nr = pow(input_nr, e, m)
    keylength = math.ceil(m.bit_length() / 8)
    crypted_data = crypted_nr.to_bytes(keylength, byteorder='big')
    print(crypted_data.hex())