1.顺时针:
You are given an n x n 2D matrix representing an image.
Rotate the image by 90 degrees (clockwise).
Note:
You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matrix and do the rotation.
Example 1:
Given input matrix = [ [1,2,3], [4,5,6], [7,8,9] ], rotate the input matrix in-place such that it becomes: [ [7,4,1], [8,5,2], [9,6,3] ]
Example 2:
Given input matrix = [ [ 5, 1, 9,11], [ 2, 4, 8,10], [13, 3, 6, 7], [15,14,12,16] ], rotate the input matrix in-place such that it becomes: [ [15,13, 2, 5], [14, 3, 4, 1], [12, 6, 8, 9], [16, 7,10,11] ]
class Solution { public: void rotate(vector<vector<int>>& matrix) { int n = matrix.size(); if (n < 2) return;
// 对行进行翻转 reverse(matrix.begin(),matrix.end()); for (int i = 0; i < n; ++i) { for (int j = i + 1;j < n;++j) { swap(matrix[i][j],matrix[j][i]); } } } };
2.逆时针
class Solution { public: void rotate(vector<vector<int>>& matrix) { int n = matrix.size(); if (n < 2) return; // 对列进行翻转 for (auto vi: matrix) reverse(vi.begin(),vi.end()); for (int i = 0; i < n; ++i) { for (int j = i + 1;j < n;++j) { swap(matrix[i][j],matrix[j][i]); } } } };