zoukankan      html  css  js  c++  java
  • 494. Target Sum

    You are given a list of non-negative integers, a1, a2, ..., an, and a target, S. Now you have 2 symbols + and -. For each integer, you should choose one from + and - as its new symbol.

    Find out how many ways to assign symbols to make sum of integers equal to target S.

    Example 1:

    Input: nums is [1, 1, 1, 1, 1], S is 3. 
    Output: 5
    Explanation: 
    
    -1+1+1+1+1 = 3
    +1-1+1+1+1 = 3
    +1+1-1+1+1 = 3
    +1+1+1-1+1 = 3
    +1+1+1+1-1 = 3
    
    There are 5 ways to assign symbols to make the sum of nums be target 3.
    

    Note:

    1. The length of the given array is positive and will not exceed 20.
    2. The sum of elements in the given array will not exceed 1000.
    3. Your output answer is guaranteed to be fitted in a 32-bit integer.

     方法1:递归暴力解决(效果较差,仅比6%的人快)

    class Solution {
    public:
    
        void help(vector<int>& nums, int i, int sum, int target, int &count)
        {
            if (i + 1 == nums.size() && sum == target)count++;
            else if (i + 1 == nums.size() && sum != target)return ;
            else
            {
                help(nums, i + 1, sum + nums[i + 1], target, count);
                help(nums, i + 1, sum - nums[i + 1], target, count);
            }
        }
        int findTargetSumWays(vector<int>& nums, int S) {
            if (nums.size() < 1) return 0;
            int count = 0;
            help(nums, 0, nums[0], S, count);
            help(nums, 0, -nums[0], S, count);
            return count;
        }
    };

    方法2:动态规划(没看懂,待学习)

  • 相关阅读:
    工作流调度器azkaban
    日志采集框架Flume
    MAPREDUCE框架结构及核心运行机制
    Python爬虫开发系列之五》数据存储为TXT、JSON格式
    Python爬虫开发系列之二》请求库及解析库安装
    策略模式+简单工厂模式
    简单工厂模式
    单例模式
    5、计算高可用
    4、存储高可用
  • 原文地址:https://www.cnblogs.com/qiang-wei/p/12271263.html
Copyright © 2011-2022 走看看