PATA 1065 A+B and C (64bit)

1065. A+B and C (64bit) (20)

时间限制

100 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

HOU, Qiming

Given three integers A, B and C in [-2⁶³, 2⁶³], you are supposed to tell whether A+B > C.

Input Specification:

The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:

For each test case, output in one line "Case #X: true" if A+B>C, or "Case #X: false" otherwise, where X is the case number (starting from 1).

Sample Input:

3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0

Sample Output:

Case #1: false
Case #2: true
Case #3: false

#include <cstdio>
int main(){
	long long a, b, c;//必须用long long 存储abc
	int T, num = 0;
	bool flag;
	scanf("%d", &T); 
	while (T--)
	{
		scanf("%lld%lld%lld", &a, &b, &c);
		long long t = a + b;
		if (a > 0 && b > 0 && t < 0)	flag = true; //正溢出
		else if (a < 0 && b < 0 && t >= 0)	flag = false;//负溢出
		else if (t > c)	flag = true;  //未溢出
		else flag = false;
		num++;
		if (flag) printf("Case #%d: true
",num);
		else printf("Case #%d: false
", num);

	}
	return 0;
}