Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.
- push(x) -- Push element x onto stack.
- pop() -- Removes the element on top of the stack.
- top() -- Get the top element.
- getMin() -- Retrieve the minimum element in the stack.
class MinStack { //使用两个栈,一个正常使用,一个保存已经压栈中最小的数,每次push和pop注意两个栈同时操作 private Stack<Integer> min=new Stack<Integer>(); private Stack<Integer> stack=new Stack<Integer>(); public void push(int x) { stack.push(x); if(min.empty()||x<min.peek()){//注意min判空 min.push(x); }else{ min.push(min.peek()); } } public void pop() { stack.pop(); min.pop(); } public int top() { return stack.peek(); } public int getMin() { return min.peek(); } }