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  • leetcode 17 Letter Combinations of a Phone Number

    Given a string containing digits from 2-9 inclusive, return all possible letter combinations that the number could represent.

    A mapping of digit to letters (just like on the telephone buttons) is given below. Note that 1 does not map to any letters.

    Example:

    Input: "23"
    Output: ["ad", "ae", "af", "bd", "be", "bf", "cd", "ce", "cf"].
    

    Note:

    Although the above answer is in lexicographical order, your answer could be in any order you want.

     
    思路:回溯法
     1 class Solution {
     2 private:
     3     // 创建映射map
     4     unordered_map<char, string> num2char {{'2', "abc"}, {'3', "def"}, {'4', "ghi"}, {'5', "jkl"},
     5                                           {'6', "mno"}, {'7', "pqrs"}, {'8', "tuv"}, {'9', "wxyz"}};
     6     
     7     void letterCombinations(vector<string> &res, string &combination, string digits, int index, int len) {
     8         if (index == len) {
     9             res.push_back(combination);
    10             return;
    11         }
    12         //遍历第index位可以选择的字符
    13         for (char c : num2char[digits[index]]) {
    14             combination.push_back(c);
    15             letterCombinations(res, combination, digits, index + 1, len);
    16             combination.pop_back();
    17         } 
    18         /*
    19         string current = num2char[digits[index]];
    20         for (int i = 0; i < current.length(); i++) {
    21             combination.push_back(current[i]);
    22             letterCombinations(res, combination, digits, index + 1, len);
    23             combination.pop_back();
    24         } */
    25     }
    26 public:
    27     vector<string> letterCombinations(string digits) {
    28     
    29         int len = digits.length();
    30         vector<string> res;
    31         if (len == 0) {
    32             return res;
    33         }
    34         
    35         string combination;
    36         letterCombinations(res, combination, digits, 0, len);
    37         return res;
    38     }
    39 };
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  • 原文地址:https://www.cnblogs.com/qinduanyinghua/p/11428161.html
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