A C
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 4830 Accepted Submission(s): 3115
Problem Description
Are you excited when you see the title "AC" ? If the answer is YES , AC it ;
You must learn these two combination formulas in the school . If you have forgotten it , see the picture.
![](http://acm.hdu.edu.cn/data/images/C53-1001-1.jpg)
Now I will give you n and m , and your task is to calculate the answer .
You must learn these two combination formulas in the school . If you have forgotten it , see the picture.
![](http://acm.hdu.edu.cn/data/images/C53-1001-1.jpg)
Now I will give you n and m , and your task is to calculate the answer .
Input
In the first line , there is a integer T indicates the number of test cases. Then T cases follows in the T lines. Each case contains a character 'A' or 'C', two integers represent n and m. (1<=n,m<=10)
Output
For each case , if the character is 'A' , calculate A(m,n),and if the character is 'C' , calculate C(m,n). And print the answer in a single line.
Sample Input
2
A 10 10
C 4 2
Sample Output
3628800
6
1 #include <iostream> 2 using namespace std; 3 int f[11] = {1, 1}; 4 5 6 int main(){ 7 for(int i = 2; i < 11; i++){ 8 f[i] = i * f[i-1]; 9 } 10 int test, n, m; 11 char c; 12 cin >> test; 13 while(test--){ 14 cin >> c >> n >> m; 15 if(c == 'A') 16 cout << f[n] / f[n - m] << endl; 17 else if(c == 'C') 18 cout << f[n] / f[m] / f[n - m] << endl; 19 } 20 return 0; 21 }