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  • C#版 大数计算器减法

    class BigReduce : BigCalculate
     

       {
            public override string Oper(string num1, string num2)
            {
                bool isMinus = false;
                //先判断计算结果是否为正数(即num1是否大于num2),如果相等,直接返回0
                //若结果为负数,则互换num1,num2,并在返回值前加'-'
                if (num1.Equals(num2))
                {
                    return "0";
                }
                else if (Max(num1, num2).Equals(num2))//如果预计计算结果为负数,则将num1 num2调换
                {
                    ChangeNum(ref num1, ref num2);
                    isMinus = true;
                }

                #region MyRegion
                //获得较大数的位数
                int len = num1.Length > num2.Length ? num1.Length : num2.Length;
                //将较小数差位补0
                string tempNum1 = new string('0', len - num1.Length) + num1;
                string tempNum2 = new string('0', len - num2.Length) + num2;

                int flag = 0;//进位符
                List liCh = new List();//存放运算后数字
                for (int i = len - 1; i >= 0; i--)
                {
                    if (tempNum1[i] >= tempNum2[i] + flag)
                    {
                        liCh.Add((char)(tempNum1[i] - tempNum2[i] - flag + '0'));
                        flag = 0;
                    }
                    else
                    {
                        liCh.Add((char)(tempNum1[i] - tempNum2[i] - flag + 10 + '0'));
                        flag = 1;
                    }
                }

                //若结果高位有0,则去掉
                //若结果为负数,则返回结果加"-"
                if (isMinus == true)
                {
                    return "-" + InvertOrder(new string(liCh.ToArray())).TrimStart('0');
                }
                return InvertOrder(new string(liCh.ToArray())).TrimStart('0');
                #endregion

            }
    }
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  • 原文地址:https://www.cnblogs.com/qiuyeyaozhuai/p/2719084.html
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