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  • 关于mysql中数据存储复合树形结构,查询时结果按树形结构输出

    1、主要思想:根据已有数据,规则性的造数据

    select * FROM(
    select lId,strName,lId as lParentId,-1 as orderIdx from tbClassify WHERE lParentId  = 0
    UNION ALL
    (select t1.* from tbClassify t1 join
    (select lId from tbClassify where lParentId=0 order by orderIdx) t2 on
    t1.lParentId = t2.lId
    where 1=1 order by t1.lParentId,t1.orderIdx)
    ) tbLast where 1=1 GROUP BY tbLast.lParentId,tbLast.lId ORDER BY tbLast.lParentId,tbLast.orderIdx
    ;

    上面的排序有问题,最后成型:

    select lId FROM(
     select lId,orderIdx as pIdx,-1 as sIdx from tbClassify WHERE lParentId  = 0
      UNION ALL
     (select a.lId,b.orderIdx pIdx,a.orderIdx sIdx from tbClassify a left JOIN tbClassify b on (a.lParentId = b.lId ) where a.lParentId != 0)
    )
    tbLast ORDER BY tbLast.pIdx,tbLast.sIdx
    ;

     该方法缺陷:前提必须知道树形结构共有几层,不带有通用型,当前方法只适用于两层树形结构,重点是提供了一种解决问题的思路:根据已有数据造数据

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  • 原文地址:https://www.cnblogs.com/qiyongliang/p/3363804.html
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