- 题目描述：
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This time, you are supposed to find A+B where A and B are two matrices, and then count the number of zero rows and columns.
- 输入：
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The input consists of several test cases, each starts with a pair of positive integers M and N (≤10) which are the number of rows and columns of the matrices, respectively. Then 2*M lines follow, each contains N integers in [-100, 100], separated by a space. The first M lines correspond to the elements of A and the second M lines to that of B.
The input is terminated by a zero M and that case must NOT be processed.
- 输出：
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For each test case you should output in one line the total number of zero rows and columns of A+B.
- 样例输入：
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2 2 1 1 1 1 -1 -1 10 9 2 3 1 2 3 4 5 6 -1 -2 -3 -4 -5 -6 0
- 样例输出：
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1 5
下面是最简单的解法，不过程序本身复杂度不高，所以可以通过：
1 import java.util.Scanner; 2 3 public class Main{ 4 public static void main(String[] args){ 5 Scanner in=new Scanner(System.in); 6 int M,N; 7 M=in.nextInt(); 8 while(M!=0){ 9 N=in.nextInt(); 10 in.nextLine(); 11 int[][]a=new int[M][N]; 12 int[][]b=new int[M][N]; 13 for(int i=0;i<M;i++){ 14 for(int j=0;j<N;j++){ 15 a[i][j]=in.nextInt(); 16 } 17 in.nextLine(); 18 } 19 for(int i=0;i<M;i++){ 20 for(int j=0;j<N;j++){ 21 b[i][j]=in.nextInt()+a[i][j]; 22 } 23 in.nextLine(); 24 } 25 int cout=0; 26 for(int i=0;i<M;i++){ 27 boolean bo=true; 28 for(int j=0;j<N;j++){ 29 if(b[i][j]!=0) 30 bo=false; 31 } 32 if(bo) 33 cout++; 34 } 35 for(int i=0;i<N;i++){ 36 boolean bo=true; 37 for(int j=0;j<M;j++){ 38 if(b[j][i]!=0) 39 bo=false; 40 } 41 if(bo) 42 cout++; 43 } 44 System.out.println(cout); 45 M=in.nextInt(); 46 } 47 } 48 } 49 /************************************************************** 50 Problem: 1001 51 User: 0000H 52 Language: Java 53 Result: Accepted 54 Time:930 ms 55 Memory:18872 kb 56 ****************************************************************/