Linux获取毫秒级时间

在软件设计中经常会用到关于时间的处理，用来计算语句、函数的执行时间，这时就需要精确到毫秒甚至是微妙的时间。

int gettimeofday(struct timeval *tv, struct timezone *tz);

int settimeofday(const struct timeval *tv , const struct timezone *tz);

 

struct timeval {

    time_t      tv_sec;     /* seconds */

    suseconds_t tv_usec;    /* microseconds */

};

 

struct timezone {

    int tz_minuteswest;     /* minutes west of Greenwich */

    int tz_dsttime;         /* type of DST correction */

};

下面是个简单的例子，用来统计程序的执行时间：

       …

struct timeval t_start,t_end;

    long cost_time = 0;

//get start time

gettimeofday(&t_start, NULL);

printf("Start time: %ld us", t_start.tv_usec);

//some operation

…

//get end time

gettimeofday(&t_end, NULL);

printf("End time: %ld us", t_end.tv_usec);

//calculate time slot

cost_time = t_end.tv_usec - t_start.tv_usec;

printf("Cost time: %ld us", cost_time);

…

输出：

Start time: 438061 us

End time: 459867 us

Cost time: 21806 us

demo:

#include <stdio.h>
#include <stdlib.h>
#include <sys/time.h>
int main(int argc, char *argv[])
{
printf("Hello, world!\n");
struct timeval tvafter,tvpre;
struct timezone tz;
int sum = 0;      
int i=0;
gettimeofday (&tvpre , &tz);

for(i = 0; i < 100000000; i++)
{
     sum += i;
}      
gettimeofday (&tvafter , &tz);
printf("sum=%d 花费时间:%d\n",sum, (tvafter.tv_sec-tvpre.tv_sec)*1000+(tvafter.tv_usec-tvpre.tv_usec)/1000);
return EXIT_SUCCESS;
}