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  • 优先级队列-堆实现

      1 package sorts;
      2 
      3 import java.util.ArrayList;
      4 import java.util.List;
      5 import java.util.Random;
      6 
      7 public class PriorityQueue<T extends Comparable<T>> { // min-heap
      8     private List<T> heap = new ArrayList<>();
      9     private static final int ROOT_INDEX = 0;
     10     private static final int PRE_ROOT_INDEX = ROOT_INDEX - 1;
     11     public void offer(T obj) {
     12         heap.add(obj);//在最后增加一个元素
     13         int index = heap.size() - 1;//最后一个元素的索引
     14         while (index > ROOT_INDEX) {//在堆中加一个元素后,调整堆使其再成为一个堆
     15             index = stepUpHeap(index);//上浮
     16         }
     17     }
     18     private int stepUpHeap(int index) {
     19         int parentIndex = parent(index);//获取父节点的索引
     20         T element = heap.get(index);
     21         T parent  = heap.get(parentIndex);
     22         if (parent.compareTo(element) > 0) { //父节点大于儿子节点,交换
     23               heap.set(parentIndex, element);
     24               heap.set(index, parent);
     25               return parentIndex;  // 跳到父索引
     26          } else   
     27               return ROOT_INDEX; //不需要交换
     28     }
     29     public T poll() {
     30         if (isEmpty())
     31             throw new RuntimeException();
     32         int index = heap.size() - 1;//最后一个元素的索引
     33         T least;
     34         if(index==0){
     35            least = heap.get(index);
     36            heap.remove(index);
     37         }
     38         else{
     39             T element = heap.get(index);//取最后一个元素
     40             least  = heap.get(ROOT_INDEX);//取堆的根元素
     41             heap.set(ROOT_INDEX, element);//交换这两个元素
     42             heap.set(index, least);
     43             heap.remove(index);//删除最后一个元素
     44             stepDownHeap(ROOT_INDEX);//下沉调整,使之再次成为堆
     45          }
     46          return least;
     47     }
     48     private void stepDownHeap(int index) {
     49         int p = index;//parent
     50         int lchild = lchild(p);//左子节点
     51         T temp = heap.get(p);
     52         while(lchild<heap.size()){
     53         if(lchild+1<heap.size() && heap.get(lchild+1).compareTo(heap.get(lchild))<0)//右节点比左节点小
     54             lchild = lchild + 1;//取两个儿子节点中小的一个
     55             if(temp.compareTo(heap.get(lchild))<=0)//不需要调整了
     56                     break;
     57             else {
     58                  heap.set(p,heap.get(lchild));//较小的儿子节点上浮
     59                  p = lchild;
     60                  lchild = lchild(p);//继续调整
     61             }
     62         }
     63         heap.set(p,temp);//最后要将temp放到p
     64     }
     65     public T peek() {
     66         if (isEmpty())
     67             throw new RuntimeException();
     68         return heap.get(0);
     69     }
     70     public boolean isEmpty() {
     71         return heap.isEmpty();
     72     }
     73     public int size() {
     74         return heap.size();
     75     }
     76     @Override
     77     public String toString() {
     78         return heap.toString();
     79     }
     80     // index starts from 0
     81     private int parent(int index) {
     82         if (index%2==0) {
     83             return ( index / 2 ) - 1;
     84         } else {
     85             return index / 2;
     86         }
     87     }
     88     private int lchild(int index) {
     89         return index * 2 + 1;
     90     }
     91     private int rchild(int index) {
     92         return index * 2 + 2;
     93     }
     94     // test
     95     public static void main(String[] args) {
     96         Random random = new Random();
     97         PriorityQueue<Integer> pq = new PriorityQueue<>();
     98         for (int i = 0; i < 10; i++) {
     99             pq.offer(random.nextInt(100));
    100         }
    101         for (int i = 0; i < 10; i++) {
    102             System.out.print(pq.poll() + " ");
    103         }
    104     }
    105 }
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  • 原文地址:https://www.cnblogs.com/qrlozte/p/3959338.html
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