poj1918

在使用printf时，%后面跟-号表示左对齐，否则右对齐。％后跟0表示用0补齐，否则表示用空格补齐，％后跟数字表示对齐宽度。

例如：％-05s，表示宽度为5右对齐输出s，左面空余区域用0补齐。

简单题

#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <algorithm>
using namespace std;

#define maxn 25
#define maxl 15
#define maxp 15

struct Team
{
    int id, penalty;
    int tot;
    int rank;
} team[maxn];

int n, p, m;
char name[maxn][maxl];
bool solve[maxn][maxp];
int wrong[maxn][maxp];

int getid(char *st)
{
    for (int i = 0; i < n; i++)
        if (strcmp(name[i], st) == 0)
            return i;
    return -1;
}

void input()
{
    scanf("%d", &n);
    for (int i = 0; i < n; i++)
    {
        scanf("%s", name[i]);
        team[i].id = i;
        team[i].penalty = team[i].tot = 0;
    }
    scanf("%d%d", &p, &m);
    memset(solve, 0, sizeof(solve));
    memset(wrong, 0, sizeof(wrong));
    for (int i = 0; i < m; i++)
    {
        int a, b;
        char correct[maxl], t[maxl];
        scanf("%d%d%s%s", &a, &b, correct, t);
        int id = getid(t);
        if (solve[id][a])
            continue;
        if (strcmp(correct, "Yes") == 0)
        {
            solve[id][a] = true;
            team[id].penalty += b + wrong[id][a] * 20;
            team[id].tot++;
            continue;
        }
        wrong[id][a]++;
    }
}

bool operator <(const Team &a, const Team &b)
{
    if (a.tot != b.tot)
        return a.tot > b.tot;
    if (a.penalty != b.penalty)
        return a.penalty < b.penalty;
    return strcmp(name[a.id], name[b.id]) < 0;
}

void work()
{
    for (int i = 0; i < n; i++)
    {
        if (i == 0 || team[i].tot != team[i - 1].tot || team[i].penalty
                != team[i - 1].penalty)
            team[i].rank = i + 1;
        else
            team[i].rank = team[i - 1].rank;
        printf("%2d. %-8s% 2d% 5d\n", team[i].rank, name[team[i].id], team[i].tot, team[i].penalty);
    }
}

int main()
{
    //freopen("t.txt", "r", stdin);
    int t;
    scanf("%d", &t);
    while (t--)
    {
        input();
        sort(team, team + n);
        work();
        putchar('\n');
    }
    return 0;
}