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  • 案例代码 -- 日历打印

    作业⼆:
    设计⼀个万年历
    要求从键盘输⼊⼀个年份和⽉份,能够打印该⽉份从详细⽇历
    提示:1900年的1⽉1⽇为星期⼀。

    package calendar;
    
    import java.util.Scanner;
    
    /**
     * 根据用户输入的年份和月份完成当月日历的绘制
     * 
     * @author GXC
     *
     */
    public class Calendar {
    
    	public static void main(String[] args) {
    
    		Scanner sc = new Scanner(System.in);
    		System.out.print("请输入所要打印的日历年份:");
    
    		int year = sc.nextInt();
    		System.out.print("请输入所要打印的日历月份:");
    		int month = sc.nextInt();
    
    		draw(year, month);
    
    	}
    
    	/**
    	 * 计算所输入年月的天数
    	 * 
    	 * @param year  用户所输入的年份
    	 * @param month 用户所输入的月份
    	 * @return 所输入月份的天数
    	 */
    	public static int dayOfThisYearMonth(int year, int month) {
    		int monthDay = 0;
    		switch (month) {
    		case 1:
    		case 3:
    		case 5:
    		case 7:
    		case 8:
    		case 10:
    		case 12:
    			monthDay = 31;
    			break;
    		case 4:
    		case 6:
    		case 9:
    		case 11:
    			monthDay = 30;
    			break;
    		case 2:
    			if (isLeapyear(2020)) {
    				monthDay = 29;
    			} else {
    				monthDay = 28;
    			}
    
    		}
    		return monthDay;
    	}
    
    	/**
    	 * 绘制日历
    	 * 
    	 * @param year  用户输入的年份
    	 * @param month 用户输入的月份
    	 */
    	public static void draw(int year, int month) {
    		int days = daysCount(year, month);
    		int monthDay = dayOfThisYearMonth(year, month);
    		int weekDay = (days) % 7;
    
    		String[] arr = { "星期日", "星期一", "星期二", "星期三", "星期四", "星期五", "星期六" };
    
    		for (int i = 0; i < 7; i++) {
    
    			System.out.print(arr[i] + "	");
    		}
    
    		System.out.println();
    
    		for (int i = 0; i < weekDay + 1; i++) {
    			System.out.print("" + "	");
    		}
    
    		int count = 1;
    
    		for (int i = weekDay + 1; i < 7; i++) {
    			System.out.print(count + "	");
    			count++;
    		}
    		System.out.println();
    
    		flag: while (count <= monthDay) {
    			for (int i = 0; i < 7; i++) {
    				System.out.print(count++ + "	");
    				if ((monthDay + 1) == count) {
    					break flag;
    				}
    			}
    
    			System.out.println();
    		}
    	}
    
    	/**
    	 * 计算1900年至用户所输入月份的上一月份总天数
    	 * 
    	 * @param year  用户输入的年份
    	 * @param month 用户输入的月份
    	 * @return 总天数
    	 */
    	public static int daysCount(int year, int month) {
    		int leapYear = 0;
    
    		for (int i = 1900; i < year; i++) {
    			if (isLeapyear(i)) {
    				leapYear++;
    			}
    		}
    
    		int thisYearDay = monthDay(year, month);
    
    		return 366 * leapYear + (year - leapYear - 1900) * 365 + thisYearDay;
    	}
    
    	/**
    	 * 判断年份是否为闰年
    	 * 
    	 * @param year
    	 * @return
    	 */
    	public static boolean isLeapyear(int year) {
    		return (year % 4 == 0 & year % 100 != 0) || (year % 400 == 0) ? true : false;
    	}
    
    	/**
    	 * 判断所输入年份的月份之前的总天数
    	 * 
    	 * @param year
    	 * @param month
    	 * @return
    	 */
    	public static int monthDay(int year, int month) {
    		boolean leapMonth = isLeapyear(year);
    
    		int leapMonthDay = 28;
    		int thisYearDay = 0;
    
    		if (leapMonth) {
    			leapMonthDay = 29;
    		}
    		switch (month) {
    		case 1:
    			thisYearDay = 0;
    			break;
    		case 2:
    			thisYearDay = 31;
    			break;
    		case 3:
    			thisYearDay = leapMonthDay + 31;
    			break;
    		case 4:
    			thisYearDay = leapMonthDay + 62;
    			break;
    		case 5:
    			thisYearDay = leapMonthDay + 92;
    			break;
    		case 6:
    			thisYearDay = leapMonthDay + 123;
    			break;
    		case 7:
    			thisYearDay = leapMonthDay + 153;
    			break;
    		case 8:
    			thisYearDay = leapMonthDay + 184;
    			break;
    		case 9:
    			thisYearDay = leapMonthDay + 215;
    			break;
    		case 10:
    			thisYearDay = leapMonthDay + 245;
    			break;
    		case 11:
    			thisYearDay = leapMonthDay + 276;
    			break;
    		case 12:
    			thisYearDay = leapMonthDay + 306;
    			break;
    
    		}
    		return thisYearDay;
    
    	}
    }
    
    
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  • 原文地址:https://www.cnblogs.com/raising/p/12913947.html
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