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  • BZOJ4007 [JLOI2015]战争调度

    根本想不出来。。。

    原来还是暴力出奇迹啊QAQ

    无限ymymym中

     1 /**************************************************************
     2     Problem: 4007
     3     User: rausen
     4     Language: C++
     5     Result: Accepted
     6     Time:240 ms
     7     Memory:13216 kb
     8 ****************************************************************/
     9  
    10 #include <cstdio>
    11 #include <cstring>
    12 #include <algorithm>
    13  
    14 using namespace std;
    15 const int N = (1 << 10) + 5;
    16  
    17 int n, m, ans;
    18 int a[N][N], b[N][N], f[N][N];
    19 int now[N];
    20  
    21 inline int read();
    22  
    23 #define ls p << 1
    24 #define rs p << 1 | 1
    25 void dfs(int p, int sz) {
    26     int i, j, mnl, mxl, tot;
    27     if (sz == 1) {
    28         f[p][0] = f[p][1] = 0;
    29         for (i = p >> 1; i; i >>= 1)
    30             if (now[i] == 0) f[p][1] += a[p][i];
    31             else f[p][0] += b[p][i];
    32         return;
    33     }
    34     tot = min(sz, m);
    35     memset(f[p], 0, sizeof(f[0][0]) * (tot + 1));
    36     now[p] = 0;
    37     dfs(ls, sz >> 1), dfs(rs, sz >> 1);
    38     for (i = 0; i <= tot; ++i) {
    39         mnl = max(i - (sz >> 1), 0), mxl = min(sz >> 1, i);
    40         for (j = mnl; j <= mxl; ++j)
    41             f[p][i] = max(f[p][i], f[ls][j] + f[rs][i - j]);
    42     }
    43      
    44     now[p] = 1;
    45     dfs(ls, sz >> 1), dfs(rs, sz >> 1);
    46     for (i = 0; i <= tot; ++i) {
    47         mnl = max(i - (sz >> 1), 0), mxl = min(sz >> 1, i);
    48         for (j = mnl; j <= mxl; ++j)
    49             f[p][i] = max(f[p][i], f[ls][j] + f[rs][i - j]);
    50     }   
    51 }
    52 #undef ls
    53 #undef rs
    54  
    55 int main() {
    56     int i, j;
    57     n = read(), m = read();
    58     for (i = 1 << n - 1; i < 1 << n; ++i)
    59         for (j = i >> 1; j; j >>= 1)
    60             a[i][j] = read();
    61     for (i = 1 << n - 1; i < 1 << n; ++i)
    62         for (j = i >> 1; j; j >>= 1)
    63             b[i][j] = read();
    64     dfs(1, 1 << n - 1);
    65     for (ans = i = 0; i <= m; ++i)
    66         ans = max(ans, f[1][i]);
    67     printf("%d
    ", ans);
    68     return 0;
    69 }
    70  
    71 inline int read() {
    72     static int x;
    73     static char ch;
    74     x = 0, ch = getchar();
    75     while (ch < '0' || '9' < ch)
    76         ch = getchar();
    77     while ('0' <= ch && ch <= '9') {
    78         x = x * 10 + ch - '0';
    79         ch = getchar();
    80     }
    81     return x;
    82 }
    View Code
    By Xs酱~ 转载请说明 博客地址:http://www.cnblogs.com/rausen
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  • 原文地址:https://www.cnblogs.com/rausen/p/4448810.html
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