zoukankan      html  css  js  c++  java
  • Count and Say

    The count-and-say sequence is the sequence of integers beginning as follows:
    1, 11, 21, 1211, 111221, ...

    1 is read off as "one 1" or 11.
    11 is read off as "two 1s" or 21.
    21 is read off as "one 2, then one 1" or 1211.

    Given an integer n, generate the nth sequence.

    Note: The sequence of integers will be represented as a string.

     1 public class Solution {
     2     public String countAndSay(int n) {
     3         // Note: The Solution object is instantiated only once and is reused by each test case.
     4         if(n < 1) return null;
     5         StringBuffer first = new StringBuffer();
     6         StringBuffer second = new StringBuffer();
     7         first.append(1);
     8         int a = 1;
     9         while(a < n){
    10             char per = first.charAt(0);
    11             int countf = 1;
    12             for(int i = 1; i < first.length(); i ++){
    13                 if(per == first.charAt(i)){
    14                     countf ++;
    15                 }else{
    16                     second.append(countf);
    17                     second.append(per);
    18                     per = first.charAt(i);
    19                     countf = 1;
    20                 }
    21             }
    22             second.append(countf);
    23             second.append(per);
    24             first = second;
    25             second = new StringBuffer();
    26             a ++;
    27         }
    28         return first.toString();
    29     }
    30 }

     第二遍:

     1 public class Solution {
     2     public String countAndSay(int n) {
     3         // Note: The Solution object is instantiated only once and is reused by each test case.
     4         if(n < 1) return null;
     5         String result = "1";
     6         for(int i = 0; i < n - 1; i ++){
     7             StringBuffer sb = new StringBuffer();
     8             int count = 1;
     9             char c = result.charAt(0);
    10             for(int j = 1; j < result.length(); j ++){
    11                 if(c != result.charAt(j)){
    12                     sb.append(count);
    13                     sb.append(c);
    14                     c = result.charAt(j);
    15                     count = 1;
    16                 }else{
    17                     count ++;
    18                 }
    19             }
    20             sb.append(count);
    21             sb.append(c);
    22             result = sb.toString();
    23         }
    24         return result;
    25     }
    26 }

     第三遍:

     1 public class Solution {
     2     public String countAndSay(int n) {
     3         String result = "1";
     4         if(n <= 1) return result;
     5         StringBuilder sb = new StringBuilder();
     6         while(n > 1){
     7             int count = 0;
     8             sb = new StringBuilder();
     9             for(int i = 0; i < result.length(); i ++){
    10                 if(i == 0 || result.charAt(i) == result.charAt(i - 1)) count ++;
    11                 else{
    12                     sb.append(count);
    13                     sb.append(result.charAt(i - 1));
    14                     count = 1;
    15                 }
    16             }
    17             sb.append(count);
    18             sb.append(result.charAt(result.length() - 1));
    19             result = sb.toString();
    20             n --;
    21         }
    22         return result;
    23     }
    24 }
  • 相关阅读:
    python 数据类型
    python核心语法
    python 基础知识
    format 用法
    有关python 函数参数
    模拟,队列与堆栈
    字符编码
    [LeetCode] Set Matrix Zeroes
    [LeetCode] Rotate Image
    [LeetCode] Unique Paths
  • 原文地址:https://www.cnblogs.com/reynold-lei/p/3365035.html
Copyright © 2011-2022 走看看