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  • AHU-61 Lake Counting (并查集)

    这里写图片描述


    简单并查集

    Code

     1 #include<bits/stdc++.h>
     2 using namespace std;
     3 const int MAXN = 10000 + 10;
     4 const int dx[] = {1, -1, 0, 0, 1, -1, 1, -1};
     5 const int dy[] = {0, 0, 1, -1, 1, -1, -1, 1};
     6 int node[MAXN], pre[MAXN];
     7 
     8 int find(int x) {
     9     return pre[x] == x ? x : pre[x] = find(pre[x]);
    10 }
    11 
    12 void join(int x, int y) {
    13     int xx = find(x);
    14     int yy = find(y);
    15     if (xx != yy) {
    16         pre[yy] = xx;
    17     }
    18 }
    19 
    20 int main() {
    21     int n, m, z;
    22     while(~scanf("%d%d", &n, &m)) {
    23         getchar();
    24         char ch;
    25         for (int i = 0; i < n; ++i) {
    26             for (int j = 0; j <= m; ++j) { //j多循环一次读换行
    27                 scanf("%c", &ch);
    28                 z = i * m + j;
    29                 if (ch == '.') node[z] = 0;
    30                 else if (ch == 'W') node[z] = 1;
    31                 pre[z] = z;
    32             }
    33         }
    34         for (int i = 0; i < n*m; ++i) {
    35             if (node[i] == 0) continue;
    36             int x = i / m, y = i % m;
    37             for (int j = 0; j < 8; ++j) {
    38                 int nx = x + dx[j], ny = y + dy[j];
    39                 if (nx < 0 || nx >= n || ny < 0 || ny >= m) continue;
    40                 int nz = nx * m + ny;
    41                 if (node[nz] == 1)
    42                     join(i, nz);
    43             }
    44         }
    45         set<int> root;
    46         for (int i = 0; i < n*m; ++i) {
    47             if (node[i] == 0) continue;
    48             int nroot = find(i);
    49             root.insert(nroot);
    50         }
    51         printf("%d
    ", root.size());
    52     }
    53 
    54     return 0;
    55 }
     
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  • 原文地址:https://www.cnblogs.com/robin1998/p/6359117.html
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