1.定义长度位5的整型数组,输入他们的值,用冒泡排序后输出.
package com.run.test; import java.util.Scanner; public class One { public static void main(String[] args) { int[] num = new int[5]; Scanner input = new Scanner(System.in); for (int i = 0; i < num.length; i++) { num[i] = input.nextInt(); } for (int i = 0; i < num.length - 1; i++) { for (int j = 0; j < num.length - 1 - i; j++) { if (num[j] > num[j + 1]) { int temp = num[j]; num[j] = num[j + 1]; num[j + 1] = temp; } } } for (int i = 0; i < num.length; i++) { System.out.print(num[i] + " "); } } }
2.定义数组{34,22,35,67,45,66,12,33},输入一个数a,查找在数组中是否存在,如果存在,输出下标,不存在输出"not found"
import java.util.Scanner; public class One { public static void main(String[] args) { Scanner input = new Scanner(System.in); boolean flag= false; int[] b = {34,22,35,67,45,66,12,33}; System.out.print("请输入一个数:"); int a = input.nextInt(); for (int i = 0; i < b.length; i++) { if (b[i] == a) { System.out.println("该数的下标是:" + i); flag = true; } } if(flag == false){ System.out.println("not found"); } } }
3.以矩阵的形式输出一个double型二维数组(长度分别为5、4,值自己设定)的值。
public class One { public static void main(String[] args) { double[][] a = { { 1.1, 3.2, 5.3, 7.4 }, { 9.1, 11,2, 13.3, 15.4 }, { 17.1, 19.2, 21.3, 23.4 }, { 25.1, 27.2, 29.3, 31.4 }, { 33, 35, 37, 39 } }; for (int i = 0; i < a.length; i++) { for (int j = 0; j < a.length - 1; j++) { System.out.print(a[i][j] + " "); } System.out.println(" "); } } }
4.定义一个二维数组(长度分别为3,4,值自己设定),求该二维数组的最大值.
public class One { public static void main(String[] args) { int[][] arr = {{11,22,33,44},{15,25,35,45},{69,66,99,96}}; int max = arr[0][0]; for(int i = 0;i<arr.length;i++) { for(int j = 0;j< arr[i].length;j++) { if(arr[i][j]>max) { max = arr[i][j]; } } }System.out.println(max); } }