题目大意
维护一个序列,支持两种操作
操作一:将第x个元素的值修改为y
操作二:询问区间【x,y】内的元素的最大值
解题分析
splay的区间操作,事先加入两个编号最小和最大的点防止操作越界。
具体的区间操作类似于线段树。
参考程序
#include <bits/stdc++.h>
using namespace std;
const int INF=2000000000;
const int N=200008;
int a[N];
class splay_tree
{
public:
struct node
{
int id,val,mx;
node *l,*r,*f;
node(int _id=0,int _val=0,int _mx=0,node *_f=NULL,node *_l=NULL,node *_r=NULL):
mx(_mx),id(_id),val(_val),f(_f),l(_l),r(_r){}
}*rt;
void pushup(node *x)
{
node *l=x->l,*r=x->r;
x->mx=x->val;
if (l) x->mx=max(x->mx,l->mx);
if (r) x->mx=max(x->mx,r->mx);
}
void right(node *x,node *&rt)
{
node *y=x->f,*z=y->f;
if (y==rt) rt=x; else if (y==z->l) z->l=x; else z->r=x;
if (x->r) x->r->f=y; y->f=x; x->f=z;
y->l=x->r; x->r=y;
pushup(y); pushup(x);
}
void left(node *x,node *&rt)
{
node *y=x->f,*z=y->f;
if (y==rt) rt=x; else if (y==z->l) z->l=x; else z->r=x;
if (x->l) x->l->f=y; y->f=x; x->f=z;
y->r=x->l; x->l=y;
pushup(y); pushup(x);
}
void splay(node *x,node *&rt)
{
while (x!=rt)
{
node *y=x->f,*z=y->f;
if (y==rt) if (x==y->l) right(x,rt); else left(x,rt);
else if (y==z->l) if (x==y->l) {right(y,rt);right(x,rt);} else {left(x,rt);right(x,rt);}
else if (x==y->r) {left(y,rt);left(x,rt);} else {right(x,rt);left(x,rt);}
}
}
void del(node *rt)
{
if (!rt) return;
del(rt->l);
del(rt->r);
delete rt;
}
splay_tree(){rt=NULL;}
~splay_tree()
{
del(rt);
}
void build(int l,int r,node *&x,node *f)
{
if (l>r) return;
int m=l+r>>1;
x=new node(m,a[m],a[m],f);
if (l==r) return;
build(l,m-1,x->l,x);
build(m+1,r,x->r,x);
pushup(x);
}
void find(int id,node* &rt)
{
node *x=rt;
while (x->id!=id)
{
if (id<x->id) x=x->l; else x=x->r;
}
splay(x,rt);
}
void update(int id,int val)
{
node *x=rt;
while (x->id!=id)
{
if (id<x->id) x=x->l; else x=x->r;
}
x->val=val;
splay(x,rt);
}
int query(int x,int y)
{
find(x-1,rt);
find(y+1,rt->r);
return rt->r->l->mx;
}
void visit(node *rt)
{
if (!rt) return;
cout<<" id = "<<rt->id<<" val = "<<rt->val;
cout<<" lson = "<<(rt->l?rt->l->id:0);
cout<<" rson = "<<(rt->r?rt->r->id:0)<<endl;
visit(rt->l);
visit(rt->r);
}
};
int main()
{
cin.sync_with_stdio(0);
int n,m;
while (cin>>n>>m)
{
splay_tree T;
for (int i=1;i<=n;i++) cin>>a[i];
a[0]=a[n+1]=0;
T.build(0,n+1,T.rt,NULL);
for (int i=1;i<=m;i++)
{
string s;int x,y;
cin>>s>>x>>y;
if (s[0]=='Q')
cout<<T.query(x,y)<<endl;
else
T.update(x,y);
}
}
}