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  • 分数排名

    Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no "holes" between ranks.

    +----+-------+
    | Id | Score |
    +----+-------+
    | 1  | 3.50  |
    | 2  | 3.65  |
    | 3  | 4.00  |
    | 4  | 3.85  |
    | 5  | 4.00  |
    | 6  | 3.65  |
    +----+-------+
    

    For example, given the above Scores table, your query should generate the following report (order by highest score):

    +-------+------+
    | Score | Rank |
    +-------+------+
    | 4.00  | 1    |
    | 4.00  | 1    |
    | 3.85  | 2    |
    | 3.65  | 3    |
    | 3.65  | 3    |
    | 3.50  | 4    |
    +-------+------+
    

    分数排名 - LeetCode (中国) https://leetcode-cn.com/problems/rank-scores/description/

     优化 简化  

    SELECT s.Score,tt.Rank FROM Scores s LEFT JOIN

    (
    SELECT (@i:=@i+1) Rank,t.* FROM (SELECT COUNT(Id) AS c,Score FROM Scores GROUP BY Score ORDER BY Score DESC ) AS t , (SELECT @i:=0) AS a
    ) AS tt ON s.Score=tt.Score ORDER BY Rank ASC;

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  • 原文地址:https://www.cnblogs.com/rsapaper/p/9094645.html
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