部门工资最高的员工 - LeetCode (中国) https://leetcode-cn.com/problems/department-highest-salary/description/
SELECT d11.Department AS Department,e11.Name AS Employee,d11.maxSalary AS Salary FROM (
SELECT MAX(Salary) AS maxSalary,d1.Name AS Department,d1.Id AS maxId FROM Employee e1 LEFT JOIN Department d1 ON e1.DepartmentId = d1.Id WHERE d1.Name IS NOT NULL GROUP BY d1.Name
) AS d11 LEFT JOIN Employee e11 ON d11.maxSalary=e11.Salary AND d11.maxId=e11.DepartmentId
ORDER BY Salary ASC
Employee 表包含所有员工信息，每个员工有其对应的 Id, salary 和 department Id 。
+----+-------+--------+--------------+ | Id | Name | Salary | DepartmentId | +----+-------+--------+--------------+ | 1 | Joe | 70000 | 1 | | 2 | Henry | 80000 | 2 | | 3 | Sam | 60000 | 2 | | 4 | Max | 90000 | 1 | | 5 | Janet | 69000 | 1 | | 6 | Randy | 85000 | 1 | +----+-------+--------+--------------+
Department 表包含公司所有部门的信息。
+----+----------+ | Id | Name | +----+----------+ | 1 | IT | | 2 | Sales | +----+----------+
编写一个 SQL 查询，找出每个部门工资前三高的员工。例如，根据上述给定的表格，查询结果应返回：
+------------+----------+--------+ | Department | Employee | Salary | +------------+----------+--------+ | IT | Max | 90000 | | IT | Randy | 85000 | | IT | Joe | 70000 | | Sales | Henry | 80000 | | Sales | Sam | 60000 | +------------+----------+--------+
SELECT D.Name AS Department,E.Name AS Employee,E.Salary AS Salary
FROM Employee AS E
INNER JOIN Department AS D
ON D.Id = E.DepartmentId
WHERE (
SELECT COUNT(DISTINCT Salary)
FROM Employee AS P4
WHERE E.DepartmentId = P4.DepartmentId
AND P4.Salary >= E.Salary
) <= 3
ORDER BY DepartmentId,Salary DESC