The 2016 ACM-ICPC Asia Qingdao Regional Contest

A - Relic Discovery

签到

#include <cstdio>
using namespace std;
int T,n;
long long ans=0;
int main()
{
    scanf("%d",&T);
    for(int t=1; t<=T; t++)
    {
        scanf("%d",&n);
        ans=0;
        for(int i=1; i<=n; i++)
        {
            int a,b;
            scanf("%d%d",&a,&b);
            ans+=a*b;
        }
        printf("%lld
",ans);
    }
    return 0;
}

　　

B - Pocket Cube

直接模拟六种转法。

#include <cstdio>

using namespace std;
int T,n;
long long ans=0;
int st[200];
int t[200];

int check()
{
    for (int j = 1; j <= 24; j += 4)
    {
        int i = j+'a'-1;
        if (t[i] != t[i+1] || t[i+1] != t[i+2] || t[i+2] != t[i+3]) return 0;
    }
    return 1;
}

int mov(char a, char b, char c, char d, char e, char f, char g, char h)
{
    int k;
    for (int i = 1; i <= 24; i++) t[i+'a'-1] = st[i+'a'-1];

    for (int i = 1; i <= 2; i++)
        k = t[a], t[a] = t[b], t[b] = t[c], t[c] = t[d], t[d] = t[e], t[e] = t[f], t[f] = t[g], t[g] = t[h], t[h] = k;
    if (check()) return 1;

    for (int i = 1; i <= 24; i++) t[i+'a'-1] = st[i+'a'-1];
    for (int i = 1; i <= 2; i++)
        k = t[h], t[h] = t[g], t[g] = t[f], t[f] = t[e], t[e] = t[d], t[d] = t[c], t[c] = t[b], t[b] = t[a], t[a] = k;
    if (check()) return 1;
    return 0;
}


int main()
{
    int T;
    scanf("%d", &T);
    for (int ca = 1; ca <= T; ca++)
    {
        for (int i = 1; i <= 24; i++) scanf("%d", &st[i+'a'-1]);
        int flag = 0;

        for (int i = 1; i <= 24; i++)
            t[i+'a'-1] = st[i+'a'-1];
        if (check()) flag = 1;
        if (mov('a','c','e','g','i','k','m','o')) flag = 1;
        if (mov('q','s','g','h','x','v','n','m')) flag = 1;
        if (mov('q','r','a','b','u','v','l','k')) flag = 1;
        if (flag) printf("YES
");
            else printf("NO
");
    }
    return 0;
}

　　

C - Pocky

记住ln(2)=0.693147。故ans = ln(L) / ln(d)。

#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
using namespace std;


int main()
{
    int t;
    scanf("%d", &t);
    for (int ca = 1; ca <= t; ca++)
    {
        double l, d;
        scanf("%lf%lf", &l, &d);
        if (l <= d) printf("0.000000
");
            else printf("%.6f
", 1+log(l/d));
    }
}

　　

D - Lucky Coins

E - Fibonacci

F - Lambda Calculus

G - Coding Contest

H - Pattern

I - Travel Brochure

J - Cliques

K - Finding Hotels

K-d树。题目数据有问题，爆搜也能过。下面的AC代码连样例都过不了。。这数据水的一批。

#include <cstdio>
#include <iostream>
#include <cstring>
#include <algorithm>
#include <queue>
#include <cmath>
#include <cstdlib>


using namespace std;
const int MAXN=2e5+100;
const int DIM=10;
inline double sqr(double x){
    return x*x;
}
namespace KDTree{
    int K;
    struct Point{
        int x[DIM];
        int price, id;
        double distance(const Point& b)const{
            double ret=0;
            for(int i=0;i<K;i++){
                ret+=sqr(x[i]-b.x[i]);
            }
            return ret;
        }
        void input(int lll){
            id = lll;
            for(int i=0;i<K;i++)scanf("%d",&x[i]);
            scanf("%d", &price);
        }
        void output(){
            printf("%d %d %d
",x[0], x[1], price);
        }
    };
    struct qnode{
        Point p;
        double dis;
        qnode(){}
        qnode(Point _p,double _dis){
            p=_p;dis=_dis;
        }
        bool operator<(const qnode &b)const{
            if (fabs(dis-b.dis) < 0.00001) return p.id < b.p.id;
            return dis<b.dis;
        }
    };
    priority_queue<qnode>q;
    struct cmpx{
        int div;
        cmpx(const int &_div){
            div=_div;
        }
        bool operator()(const Point &a,const Point &b){
            for(int i=0;i<K;i++){
                if(a.x[(div+i)%K]!=b.x[(div+i)%K]){
                    if (a.x[(div+i)%K] !=b.x[(div+i)%K]) return a.x[(div+i)%K]<b.x[(div+i)%K];
                    return a.id<b.id;
                }
            }
            return true;
        }
    };
    bool cmp(const Point &a,const Point &b,int div){
        cmpx cp=cmpx(div);
        return cp(a,b);
    }
    struct Node{
        Point e;
        Node *lc,*rc;
        int div;
    }pool[MAXN],*tail,*root;
    void init(){
        tail=pool;
    }
    Node *build(Point *a,int l,int r,int div){
        if(l>=r)return NULL;
        Node *p=tail++;
        p->div=div;
        int mid=(l+r)/2;
        nth_element(a+l,a+mid,a+r,cmpx(div));
        p->e=a[mid];
        p->lc=build(a,l,mid,(div+1)%K);
        p->rc=build(a,mid+1,r,(div+1)%K);
        return p;
    }
    void search(Point p,Node *x,int div,int m){
        if(!x)return;
        if(cmp(p,x->e,div)){
            search(p,x->lc,(div+1)%K,m);
            if(q.size()<m){
                if (x->e.price <= p.price)
                    q.push(qnode(x->e,p.distance(x->e)));
                search(p,x->rc,(div+1)%K,m);
            }else{
                if(p.distance(x->e)<q.top().dis){
                    if (x->e.price <= p.price)
                        q.pop(), q.push(qnode(x->e,p.distance(x->e)));
                }
                if(sqr(x->e.x[div]-p.x[div])<q.top().dis){
                    search(p,x->rc,(div+1)%K,m);
                }
            }
        }else{
            search(p,x->rc,(div+1)%K,m);
            if(q.size()<m){
                if (x->e.price <= p.price) q.push(qnode(x->e,p.distance(x->e)));
                search(p,x->lc,(div+1)%K,m);
            }else{
                if(p.distance(x->e)<q.top().dis){
                    if (x->e.price <= p.price)
                        q.pop(), q.push(qnode(x->e,p.distance(x->e)));
                }
                if(sqr(x->e.x[div]-p.x[div])<q.top().dis)
                    search(p,x->lc,(div+1)%K,m);
            }
        }
    }
    void search(Point p,int m){
        while(!q.empty())q.pop();
        search(p,root,0,m);
    }
};
KDTree::Point p[MAXN];
int main(){
    int t;
    scanf("%d", &t);
    for (int ca = 1; ca<=t; ca++)
    {
        int n, Q;
        scanf("%d%d",&n, &Q);
        KDTree::K=2;
        for(int i=0;i<n;i++)p[i].input(i);
        KDTree::init();
        KDTree::root=KDTree::build(p,0,n,0);


        KDTree ::Point o;
        while(Q--){
            o.input(1000000);
            int m;
            //scanf("%d",&m);
            m = 1;
            KDTree::search(o,1);
            int cnt=0;
            while(!KDTree::q.empty()){
                p[cnt++]=KDTree::q.top().p;
                KDTree::q.pop();
            }
            //printf(":::::");
            p[0].output();
            //printf("%d
", p[0].id);
        }
    }
    return 0;
}

　　

L - Tower Attack

M - Generator and Monitor