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  • 线性求逆元

    #include<cstdio>
    #include<cstring>
    const int  maxn=1e5+7;
    using namespace std;
    
    inline int read(){
      int x=0,f=1;
      char ch=getchar();
      while(ch>'9'||ch<'0'){
        if(ch=='-') f=-1;
        ch=getchar();
      }
      while(ch>='0'&&ch<='9'){
        x=(x<<1)+(x<<3)+(ch^48);
        ch=getchar();
      }
      return x*f;
    }
    long long inv[maxn];
    
    void inverse(int mod){
      inv[0]=inv[1]=1;
      for(int i=2;i<maxn;i++){
        inv[i]=((mod-mod/i)*inv[mod%i])%mod;
      }
    }
      int main(){
    int n,p;
    n=read(),p=read();
    inverse(p);
    for(int i=1;i<=n;i++){
      printf("%lld
    ",inv[i]);
    }
      return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/scy-fisheep/p/13848234.html
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