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  • [BZOJ4668]冷战

    并查集按秩合并的裸题。。。

    #include <iostream>
    #include <cstdio>
    #include <cstring>
    using namespace std;
    const int N=500005;
    int fa[N],lastans,val[N],n,Q,u,v,opt,cnt,dep[N];
    bool tong[N];
    int find(int x) {
    	if(x==fa[x]) return x;
    	int f=find(fa[x]);
    	dep[x]=dep[fa[x]]+1;
    	return f;
    }
    void merge(int x,int y) {
    	++cnt;
    	x=find(x),y=find(y);
    	if(x==y) return;
    	if(dep[x]>dep[y]) swap(x,y);
    	fa[x]=y;
    	if(dep[x]==dep[y]) dep[y]++;
    	val[x]=cnt;
    }
    int find(int x,int y) {
    	int fx=find(x),fy=find(y);
    	lastans=0;
    	if(fx!=fy) return 0;
    	while(x!=y) {
    		if(dep[x]<dep[y]) swap(x,y);
    		lastans=max(lastans,val[x]);x=fa[x];
    	}
    	return lastans;
    }
    int main() {
    	scanf("%d%d",&n,&Q);
    	for(int i=1;i<=n;i++) fa[i]=i;
    	while(Q--) {
    		scanf("%d%d%d",&opt,&u,&v);
    		switch (opt) {
    			case 0:merge(u^lastans,v^lastans);break;
    			case 1:printf("%d
    ",lastans=find(u^lastans,v^lastans));break;
    		}
    	}
    	return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/sdfzhsz/p/9828220.html
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