题目如下:
A boomerang is a set of 3 points that are all distinct and not in a straight line.
Given a list of three points in the plane, return whether these points are a boomerang.
Example 1:
Input: [[1,1],[2,3],[3,2]] Output: true
Example 2:
Input: [[1,1],[2,2],[3,3]] Output: false
Note:
points.length == 3
points[i].length == 2
0 <= points[i][j] <= 100
解题思路:本题就是判断三点是否在一条直线上,判断的方法也很简单,任意从这三个点中选取两组点对,如果这两组的点对的斜率相同,则在同一直线上。
代码如下:
class Solution(object): def isBoomerang(self, points): """ :type points: List[List[int]] :rtype: bool """ return (points[0][1]-points[1][1]) * (points[1][0]-points[2][0]) != (points[0][0]-points[1][0]) * (points[1][1]-points[2][1])