【leetcode】1507. Reformat Date

题目如下：

Given a date string in the form Day Month Year, where:

• Day is in the set {"1st", "2nd", "3rd", "4th", ..., "30th", "31st"}.
• Month is in the set {"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}.
• Year is in the range [1900, 2100].

Convert the date string to the format YYYY-MM-DD, where:

• YYYY denotes the 4 digit year.
• MM denotes the 2 digit month.
• DD denotes the 2 digit day. 

Example 1:

Input: date = "20th Oct 2052"
Output: "2052-10-20"

Example 2:

Input: date = "6th Jun 1933"
Output: "1933-06-06"

Example 3:

Input: date = "26th May 1960"
Output: "1960-05-26"

Constraints:

• The given dates are guaranteed to be valid, so no error handling is necessary.

解题思路：day去掉后缀，剩下的数字前面补0直到补齐为两位，month直接转换，year不变。

代码如下：

class Solution(object):
    def reformatDate(self, date):
        """
        :type date: str
        :rtype: str
        """
        monthes = ["","Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"]
        item = date.split(" ")

        day = item[0].replace('th','').replace('st','').replace('nd','').replace('rd','').zfill(2)
        month = str(monthes.index(item[1])).zfill(2)

        return item[2]+'-' + month + '-' + day