zoukankan      html  css  js  c++  java
  • 566. Reshape the Matrix( 改变矩阵维度)

    In MATLAB, there is a very useful function called 'reshape', which can reshape a matrix into a new one with different size but keep its original data.

    You're given a matrix represented by a two-dimensional array, and two positive integers r and c representing the rownumber and column number of the wanted reshaped matrix, respectively.

    The reshaped matrix need to be filled with all the elements of the original matrix in the same row-traversing order as they were.

    If the 'reshape' operation with given parameters is possible and legal, output the new reshaped matrix; Otherwise, output the original matrix.

    Example 1:

    Input: 
    nums = 
    [[1,2],
     [3,4]]
    r = 1, c = 4
    Output: 
    [[1,2,3,4]]
    Explanation:
    The row-traversing of nums is [1,2,3,4]. The new reshaped matrix is a 1 * 4 matrix, fill it row by row by using the previous list.

    方法一:借助中间数组
    class Solution {
        public int[][] matrixReshape(int[][] nums, int r, int c) {
            int row=nums.length;
            int col=nums[0].length;
            
            if(row*col!=r*c){
                return nums;
            }else{
                int [][] res=new int[r][c];
                int [] reseve=new int[row*col];
                int z=0;
                for(int i=0;i<row;i++){
                    for(int j=0;j<col;j++){
                        reseve[z++]=nums[i][j];
                    }
                }
                z=0;
                for(int i=0;i<r;i++){
                    for(int j=0;j<c;j++){
                        res[i][j]=reseve[z++];
                    }
                }
                return res;
            }
        }
    }

    方法二:直接转换

    class Solution {
        public int[][] matrixReshape(int[][] nums, int r, int c) {
            int row=nums.length;
            int col=nums[0].length;
            
            if(row*col!=r*c){
                return nums;
            }
            int [][] res=new int[r][c];
            int index=0;
            for(int i=0;i<r;i++){
                for(int j=0;j<c;j++){
                    res[i][j]=nums[index/col][index%col];
                    index++;
                }
            }
            return res;
        }
    }
    苟有恒,何必三更眠五更起;最无益,莫过一日暴十日寒。
  • 相关阅读:
    js实现可配置参数的轮播图
    js获取、修改CSS样式
    js值的类型和函数传参
    DOM事件
    C主函数:void main(int argc,char *argv[] )
    eclispe无法获取maven依赖的本地项目jar包
    eclipse没有server选项解决方法
    Eclipse中Tomcat的add and remove找不到项目
    java简单web爬虫(网页图片)
    (转)大前端完整学习路线(详解)
  • 原文地址:https://www.cnblogs.com/shaer/p/10864722.html
Copyright © 2011-2022 走看看