五维DP，听着挺多的，貌似就是挺裸的dp，
最近貌似做简单的DP挺顺手。。1A
dp[i][j][e][o][g] = min(dp[i][j][e][o][g],dp[i-i1][j-i2][e-i3][o-i4][g-i5]+p[q]) i1,i2...为满足给出的商品数量的值 p[q]为选用当前优惠方案的价格。
1 /* 2 ID: shangca2 3 LANG: C++ 4 TASK: shopping 5 */ 6 #include <iostream> 7 #include<cstdio> 8 #include<cstring> 9 #include<algorithm> 10 #include<stdlib.h> 11 using namespace std; 12 #define INF 0xfffffff 13 int dp[6][6][6][6][6]; 14 struct node 15 { 16 int c[6],k[6],p,n; 17 }pp[110]; 18 int c[6],k[6],p[6]; 19 int main() 20 { 21 freopen("shopping.in","r",stdin); 22 freopen("shopping.out","w",stdout); 23 int i,j,s,b,e,o,g,q,a; 24 for(i =0 ; i <= 5 ; i++) 25 for(j = 0 ; j <= 5 ; j++) 26 for(e = 0 ; e <= 5 ; e++) 27 for(o = 0 ; o <= 5 ; o++) 28 for(g = 0 ; g <= 5 ; g++) 29 dp[i][j][e][o][g] = INF; 30 cin>>s; 31 for(i = 1; i <= s ; i++) 32 { 33 cin>>pp[i].n; 34 for(j = 1; j <= pp[i].n ; j++) 35 cin>>pp[i].c[j]>>pp[i].k[j]; 36 cin>>pp[i].p; 37 } 38 cin>>b; 39 for(i = 1; i <= b ;i++) 40 cin>>c[i]>>k[i]>>p[i]; 41 for(i = 0 ;i <= k[1] ; i++) 42 for(j = 0; j <= k[2] ; j++) 43 for(e = 0; e <= k[3] ; e++) 44 for(o = 0 ; o <= k[4] ;o++) 45 for(g = 0 ; g <= k[5] ; g++) 46 { 47 dp[i][j][e][o][g] = i*p[1]+j*p[2]+e*p[3]+o*p[4]+g*p[5]; 48 for(q = 1; q <= s ; q++) 49 { 50 int i1=0,i2=0,i3=0,i4=0,i5=0; 51 for(a = 1; a <= pp[q].n ;a++) 52 { 53 if(pp[q].c[a]==c[1]) 54 i1 = pp[q].k[a]; 55 else if(pp[q].c[a]==c[2]) 56 i2 = pp[q].k[a]; 57 else if(pp[q].c[a]==c[3]) 58 i3 = pp[q].k[a]; 59 else if(pp[q].c[a]==c[4]) 60 i4 = pp[q].k[a]; 61 else 62 i5 = pp[q].k[a]; 63 } 64 if(i-i1>=0&&j-i2>=0&&e-i3>=0&&o-i4>=0&&g-i5>=0) 65 { 66 dp[i][j][e][o][g] = min(dp[i][j][e][o][g],dp[i-i1][j-i2][e-i3][o-i4][g-i5]+pp[q].p); 67 } 68 } 69 } 70 cout<<dp[k[1]][k[2]][k[3]][k[4]][k[5]]<<endl; 71 return 0; 72 }