PAT-1005 Spell It Right 解答(C/C++/Java/python)

1.Description：

2.Example：

Input:
12345
Output:
one five

3.solutions:

C Version:

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

int main() {
    char digits[] = {};
    char NUMBERS[][10] = {"zero", "one", "two", "three", "four", "five","six",
                        "seven", "eight", "nine", "ten"};
    scanf("%s", digits);
    int sum = 0;
    unsigned i;
    for (i = 0; digits != NULL && i < strlen(digits); ++i) {
        sum += digits[i] - 48;  // '0'的Ascill码为48
    }
    char* output;
    sprintf(output, "%d", sum);
    unsigned j;
    for (j = 0; output[j] != ''; ++j) {
        if (j != strlen(output) - 1)
            printf("%s ", NUMBERS[output[j] - 48]);
        else
            printf("%s", NUMBERS[output[j] - 48]);
    }
    return 0;
}

Note: 自己的电脑上调试无误，提交时运行错误！

C++ Version:

#include <iostream>
using namespace std;

int main() {
    string digits;
    string NUMBERS[] = {"zero", "one", "two", "three", "four", "five","six",
                        "seven", "eight", "nine", "ten"};
    getline(cin, digits);
    cout << digits << endl;
    int sum = 0;
    for (int i = 0; i < digits.size(); ++i) {
        sum += int(digits[i]);
    }
    string output = to_string(sum);
    for (int j = 0; j < output.size(); ++j) {
        if (j != output.size() - 1)
            cout << NUMBERS[int(output[j])] << " ";
        else
            cout << NUMBERS[int(output[j])];
    }
    return 0;
}

Java Version:

import java.util.Scanner;

/**
 * Created by sheepcore on 2020-02-28
 */

public class P1005_Spell_It_Right {
    public static void main(String[] args) {
        String digits;
        String NUMBERS[] = {"zero", "one", "two", "three", "four", "five","six",
                "seven", "eight", "nine", "ten"};
        Scanner scan = new Scanner(System.in);
        digits = scan.nextLine();
        int sum = 0;
        for (int i = 0; i < digits.length(); ++i) {
            sum += Integer.parseInt(digits.charAt(i) + "");
        }
        String output = sum + "";
        int idx;
        for (int j = 0; j < output.length(); ++j) {
            if (j != output.length() - 1){
                idx = Integer.parseInt(output.charAt(j) + "");
                System.out.print(NUMBERS[idx] + " ");
            }
            else {
                idx = Integer.parseInt(output.charAt(j) + "");
                System.out.print(NUMBERS[idx]);
            }
        }
    }
}

Python Version:

"""
    created by sheepcore on 2020-2-28
"""

if __name__ == "__main__":
    digits = input()
    NUMBERS = ['zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven',
               'eight', 'nine', 'ten']
    i = 0
    for ch in digits:  
        i += eval(ch)
    sum = str(i)
    output = ""
    for num in sum:
        output += " " + str(NUMBERS[eval(num)])
    print(output.lstrip(), end='')

4.summary:

掌握C、C++、Java、Python中字符串与数字之间的转换方法。

水滴石穿，笨鸟先飞！