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  • 最短路 之 CODE[VS] 1077 多源最短路

    /*
      floyd算法
    */
     1 #include <iostream>
     2 #include <cstdlib>
     3 #include <cstdio>
     4 #include <cstddef>
     5 #include <iterator>
     6 #include <algorithm>
     7 #include <string>
     8 #include <locale>
     9 #include <cmath>
    10 #include <vector>
    11 #include <cstring>
    12 #include <map>
    13 #include <utility>
    14 #include <queue>
    15 #include <stack>
    16 #include <set>
    17 #include <functional>
    18 using namespace std;
    19 const int INF = 0x3f3f3f3f;
    20 const int MaxN = 105;
    21 const int modPrime = 3046721;
    22 
    23 int n;
    24 int dp[MaxN][MaxN];
    25 
    26 
    27 void Solve()
    28 {
    29     for (int k = 0; k < n; ++k)
    30     {
    31         for (int i = 0; i < n; ++i)
    32         {
    33             for (int j = 0; j < n; ++j)
    34             {
    35                 dp[i][j] = min(dp[i][j], dp[i][k] + dp[k][j]);
    36             }
    37         }
    38     }
    39     int Q;
    40     scanf("%d", &Q);
    41     int src, dsn;
    42     for (int i = 0; i < Q; ++i)
    43     {
    44         scanf("%d %d", &src, &dsn);
    45         printf("%d
    ", dp[src - 1][dsn - 1]);
    46     }
    47 }
    48 
    49 int main()
    50 {
    51 #ifdef HOME
    52     freopen("in", "r", stdin);
    53     //freopen("out", "w", stdout);
    54 #endif
    55 
    56     scanf("%d", &n);
    57     for (int i = 0; i < n; ++i)
    58     {
    59         for (int j = 0; j < n; ++j)
    60         {
    61             scanf("%d", &dp[i][j]);
    62         }
    63     }
    64     Solve();
    65 
    66 #ifdef HOME
    67     cerr << "Time elapsed: " << clock() / CLOCKS_PER_SEC << " ms" << endl;
    68     _CrtDumpMemoryLeaks();
    69 #endif
    70     return 0;
    71 }
    
    
    
     
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  • 原文地址:https://www.cnblogs.com/shijianming/p/5026792.html
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