zoukankan      html  css  js  c++  java
  • 【网络流24题】火星探险问题

    题面

    https://www.luogu.org/problemnew/show/P3356

    题解

    拆点+费用流

    alpq654321讲过。

    #include<cstdio>
    #include<cstring>
    #include<iostream>
    #include<vector>
    #include<queue>
    #define N 5000
    #define INF 1000000007
    #define T (2*n*m+1)
    #define S 0
    #define LL long long
    #define ri register int
    using namespace std;
    
    int n,m,k,opt;
    
    struct graph {
      vector<int> to,w,c;
      vector<int> ed[N];
      LL dis[N]; int cur[N];
      bool vis[N];
      void add_edge(int a,int b,int aw,int ac) {
        to.push_back(b); w.push_back(aw); c.push_back(ac);  ed[a].push_back(to.size()-1);
        to.push_back(a); w.push_back(0);  c.push_back(-ac); ed[b].push_back(to.size()-1);
      }
      bool spfa() {
        memset(dis,-0x3f,sizeof(dis));
        memset(vis,0,sizeof(vis));
        queue<int> q;
        dis[S]=0;q.push(S);vis[S]=1;
        while (!q.empty()) {
          int x=q.front(); q.pop();
          for (ri i=0;i<ed[x].size();i++) {
            int e=ed[x][i];
            if (dis[to[e]]<dis[x]+c[e] && w[e]) {
              dis[to[e]]=dis[x]+c[e];
              if (!vis[to[e]]) vis[to[e]]=1,q.push(to[e]);
            }
          }
          vis[x]=0;
        }
        return dis[T]>-INF;
      }
      int dfs(int x,int lim) {
        if (x==T || !lim) return lim;
        LL sum=0; vis[x]=1;
        for (ri &i=cur[x];i<ed[x].size();i++) {
          int e=ed[x][i];
          if (dis[x]+c[e]==dis[to[e]] && w[e] && !vis[to[e]]) {
            int f=dfs(to[e],min(lim,w[e]));
            w[e]-=f; w[1^e]+=f;
            lim-=f; sum+=f;
            if (!lim) return sum;
          }
        }
        return sum;
      }
      LL zkw() {
        LL ret=0;
        while (spfa()) {
          memset(vis,0,sizeof(vis));
          memset(cur,0,sizeof(cur));
          ret+=dfs(S,INF)*dis[T];
        }
        return ret;
      }
      void print(int col,int tn) {
        if (tn==n*m) return;
        int now=n*m+tn;
        for (ri i=0;i<ed[now].size();i++) {
          int e=ed[now][i];
          if (e%2==1) continue;
          if (c[e]==1 && w[e]==0 || c[e]==0 && w[e]<INF) {
            w[e]++;
            printf("%d %d
    ",col,to[e]-tn==1?1:0);
            print(col,to[e]);
            return;
          }
        }
      }
    } G;
    
    int id1(int x,int y) {return (x-1)*m+y;}
    int id2(int x,int y) {return n*m+(x-1)*m+y;}
    
    int main() {
      scanf("%d",&k);
      scanf("%d %d",&n,&m);
      swap(n,m);
      for (ri i=1;i<=n;i++) {
        for (ri j=1;j<=m;j++) {
          scanf("%d",&opt);
          if (opt!=1) {
            G.add_edge(id1(i,j),id2(i,j),INF,0);
            if (opt==2) G.add_edge(id1(i,j),id2(i,j),1,1);
          }
        }
      }
      for (ri i=1;i<=n;i++) {
        for (ri j=1;j<=m;j++) {
          if (i+1<=n) G.add_edge(id2(i,j),id1(i+1,j),INF,0);
          if (j+1<=m) G.add_edge(id2(i,j),id1(i,j+1),INF,0);
        }
      }
      G.add_edge(S,id1(1,1),k,0);
      G.add_edge(id2(n,m),T,k,0);
      int t=G.zkw();
      for (ri i=1;i<=k;i++) G.print(i,1);
      return 0;
    }
  • 相关阅读:
    Munge
    file upload custom form
    随笔摘要
    生成css 和 清缓存
    drupal commit 原则
    Git reset --hard
    www-data
    301/302的区别
    什么是request_uri
    in_array foreach array_search的性能比较
  • 原文地址:https://www.cnblogs.com/shxnb666/p/11187905.html
Copyright © 2011-2022 走看看