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  • 【CF125E】MST Company

    题面

    https://www.luogu.org/problemnew/show/CF125E

    题解

    #include<cstdio>
    #include<iostream>
    #include<algorithm>
    #include<cstring>
    #define ri register int
    #define N 200050
    #define M 400050
    using namespace std;
    int n,m,k,cnt;
    int f[N],L[M];
    struct edge{int u,v,l;} e[M];
    bool cmp(int x,int y){return L[x]<L[y]||(L[x]==L[y]&&(min(e[x].u,e[x].v)<min(e[y].u,e[y].v)));}
    int id[N];
    bool used[N];
    int findroot(int x){
      if (f[x]==x) return x;
      return f[x]=findroot(f[x]);
    }
    bool check(int x) {
      for (ri i=1;i<=m;i++) if (e[i].u==1 || e[i].v==1) L[i]=e[i].l-x; else L[i]=e[i].l;
      for (ri i=1;i<=n;i++) f[i]=i;
      for (ri i=1;i<=m;i++) id[i]=i,used[i]=0;
      sort(id+1,id+m+1,cmp);
      int cc=0; cnt=0;
      for (ri i=1;i<=m;i++) {
        if (e[id[i]].u==1 || e[id[i]].v==1) if (cc==k) continue;
        int r1=findroot(e[id[i]].u),r2=findroot(e[id[i]].v);
        if (r1==r2) continue;
        f[r1]=r2;
        cnt++;
        used[id[i]]=1;
        if (e[id[i]].u==1 || e[id[i]].v==1) cc++;
      }
      if (cc==k) return 1; else return 0;
    }
    int main(){
      scanf("%d %d %d",&n,&m,&k);
      for (ri i=1;i<=m;i++) scanf("%d %d %d",&e[i].u,&e[i].v,&e[i].l);
      int lb=-100010,rb=100010,ans=500000;
      while (lb<=rb) {
        int mid=(lb+rb)/2;
        if (check(mid)) ans=mid,rb=mid-1; else lb=mid+1;
      }
      check(ans);
      if (ans==500000 || cnt!=n-1) {
        puts("-1");
        return 0;
      }
      printf("%d
    ",n-1);
      for (ri i=1;i<=m;i++) if (used[i]) printf("%d ",i);
      return 0;
    }
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  • 原文地址:https://www.cnblogs.com/shxnb666/p/11275522.html
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