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  • POJ 3621 Sightseeing Cows

    传送门

    AcWing 361 观光奶牛洛谷 P2868 [USACO07DEC]Sightseeing Cows G

    (frac{sum f[i]}{sum t[i]}) 极大值为 (μinleft(0,1000 ight]),采用二分搜索答案方法不断枚举 (mid)

    (frac{sum f[i]}{sum t[i]}>mid)(sum f[i]-mu*sum t[i]=sum left(f[i]-mid imes t[i] ight)>0) 成立即图中存在正环,

    则二分后一半区间,反之二分前一半区间。

    #include <iostream>
    #include <cstdio>
    #include <cstring>
    #include <cmath>
    #include <vector>
    #include <queue>
    #include <stack>
    #include <map>
    #include <set>
    #include <algorithm>
    
    using namespace std;
    typedef long long ll;
    typedef pair<int, int> p;
    const double pi(acos(-1));
    const int inf(0x3f3f3f3f);
    const int mod(1e9 + 7);
    const int maxn(1e3 + 10);
    const int maxm(6e3 + 10);
    bool vis[maxn];
    int ecnt, head[maxn], f[maxn], cnt[maxn];
    double dis[maxn];
    
    struct edge {
        int to, wt, nxt;
    } edges[maxm];
    
    template<typename T>
    inline const T read()
    {
        T x = 0, f = 1;
        char ch = getchar();
        while (ch < '0' || ch > '9') {
            if (ch == '-') f = -1;
            ch = getchar();
        }
        while (ch >= '0' && ch <= '9') {
            x = (x << 3) + (x << 1) + ch - '0';
            ch = getchar();
        }
        return x * f;
    }
    
    template<typename T>
    inline void write(T x, bool ln)
    {
        if (x < 0) {
            putchar('-');
            x = -x;
        }
        if (x > 9) write(x / 10, false);
        putchar(x % 10 + '0');
        if (ln) putchar(10);
    }
    
    void addEdge(int u, int v, int w)
    {
        edges[ecnt].to = v;
        edges[ecnt].wt = w;
        edges[ecnt].nxt = head[u];
        head[u] = ecnt++;
    }
    
    bool spfa(int n, double val)
    {
        for (int i = 1; i <= n; ++i) {
            dis[i] = -inf;
            cnt[i] = 0;
            vis[i] = false;
        }
        vis[0] = true;
        dis[0] = 0;
        queue<int> q;
        q.push(0);
        while (not q.empty()) {
            int u = q.front();
            q.pop();
            vis[u] = false;
            for (int i = head[u]; compl i; i = edges[i].nxt) {
                int v = edges[i].to, w = edges[i].wt;
                if (dis[v] < dis[u] + f[v] - val * w) {
                    dis[v] = dis[u] + f[v] - val * w;
                    if (not vis[v]) {
                        vis[v] = true;
                        q.push(v);
                        cnt[v] = cnt[u] + 1;
                        if (cnt[v] >= n + 1) {
                            return true;
                        }
                    }
                }
            }
        }
        return false;
    }
    
    int main()
    {
    #ifdef ONLINE_JUDGE
    #else
        freopen("input.txt", "r", stdin);
    #endif
        ios::sync_with_stdio(false);
        memset(head, -1, sizeof head);
        int n = read<int>(), m = read<int>();
        for (int i = 1; i <= n; ++i) {
            f[i] = read<int>();
        }
        while (m--) {
            int u = read<int>(), v = read<int>(), w = read<int>();
            addEdge(u, v, w);
        }
        for (int i = 1; i <= n; ++i) {
            addEdge(0, i, 0);
        }
        double low = 0, high = 1e3;
        while (high - low >= 1e-4) {
            double mid = (low + high) / 2;
            if (spfa(n, mid)) {
                low = mid;
            } else {
                high = mid;
            }
        }
        printf("%.2f
    ", low);
        return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/singularity2u/p/13849327.html
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