题目链接
https://leetcode.com/problems/restore-ip-addresses/
题目原文
Given a string containing only digits, restore it by returning all possible valid IP address combinations.
For example:
Given "25525511135"
,
return ["255.255.11.135", "255.255.111.35"]
. (Order does not matter)
题目大意
输入一个字符串,给出所有的可能IP的集合
解题思路
使用dfs求解。可将题目理解成在一个字符串中加入3个挡板,得到四个子字符串的值都小于255.
代码
class Solution(object):
def restoreIpAddresses(self, s):
"""
:type s: str
:rtype: List[str]
"""
def dfs(s, sub, ips, ip):
if sub == 4: # should be 4 parts
if s == '':
ips.append(ip[1:]) # remove first '.'
return
for i in range(1, 4): # the three ifs' order cannot be changed!
if i <= len(s): # if i > len(s), s[:i] will make false!!!!
if int(s[:i]) <= 255:
dfs(s[i:], sub + 1, ips, ip + '.' + s[:i])
if s[0] == '0':
break # make sure that res just can be '0.0.0.0' and remove like '00'
ips = []
dfs(s, 0, ips, '')
return ips