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  • 85.Maximal Rectangle

    class Solution {
    public:
        /**
         * @param matrix a boolean 2D matrix
         * @return an integer
         */
        int maximalRectangle(vector<vector<bool> > &matrix) {
            if (matrix.empty() || matrix[0].empty()) return 0;
            int res = 0, m = matrix.size(), n = matrix[0].size();
            vector<int> h(n + 1, 0);
            for (int i = 0; i < m; ++i) {
                stack<int> s;
                for (int j = 0; j < n + 1; ++j) {
                    if (j < n) {
                        if (matrix[i][j]) ++h[j];
                        else h[j] = 0;
                    }
                    while (!s.empty() && h[s.top()] >= h[j]) {
                        int cur = s.top(); s.pop();
                        res = max(res, h[cur] * (s.empty() ? j : (j - s.top() - 1)));
                    }
                    s.push(j);
                }
            }
            return res;
        }
    };
    
    class Solution {
    public:
        /**
         * @param matrix a boolean 2D matrix
         * @return an integer
         */
        int maximalRectangle(vector<vector<bool> > &matrix) {
            if (matrix.empty() || matrix[0].empty()) return 0;
            int res = 0, m = matrix.size(), n = matrix[0].size();
            vector<int> h(n, 0), left(n, 0), right(n, n);
            for (int i = 0; i < m; ++i) {
                int cur_left = 0, cur_right = n;
                for (int j = 0; j < n; ++j) {
                    h[j] = matrix[i][j] ? h[j] + 1 : 0;
                }
                for (int j = 0; j < n; ++j) {
                    if (matrix[i][j]) left[j] = max(left[j], cur_left);
                    else {left[j] = 0; cur_left = j + 1;}
                }
                for (int j = n - 1; j >= 0; --j) {
                    if (matrix[i][j]) right[j] = min(right[j], cur_right);
                    else {right[j] = n; cur_right = j;}
                }
                for (int j = 0; j < n; ++j) {
                    res = max(res, (right[j] - left[j]) * h[j]);
                }
            }
            return res;
        }
    };
    
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  • 原文地址:https://www.cnblogs.com/smallredness/p/10676072.html
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