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  • Java equals的一个坑

    public class StringEqualsObject {
        public static void main(String[] args) {
    
            String name="Tom";
            Person p=new Person(name);
            System.out.println(name.equals(p));
            System.out.println("p.toString():"+name.equals(p.toString()));
            System.out.println(p.equals(name));
        }
    
    }
    
    class Person{
        private String name;
    
        public Person(String name) {
            super();
            this.name = name;
        }
    
        @Override
        public String toString() {
            return this.name;
        }
    }

    Output:

    false
    p.toString():true
    false

    原因:
    java.lang.String

      /**
         * Compares this string to the specified object.  The result is {@code
         * true} if and only if the argument is not {@code null} and is a {@code
         * String} object that represents the same sequence of characters as this
         * object.
         *
         * @param  anObject
         *         The object to compare this {@code String} against
         *
         * @return  {@code true} if the given object represents a {@code String}
         *          equivalent to this string, {@code false} otherwise
         *
         * @see  #compareTo(String)
         * @see  #equalsIgnoreCase(String)
         */
        public boolean equals(Object anObject) {
        if (this == anObject) {
            return true;
        }
        if (anObject instanceof String) {
            String anotherString = (String)anObject;
            int n = count;
            if (n == anotherString.count) {
            char v1[] = value;
            char v2[] = anotherString.value;
            int i = offset;
            int j = anotherString.offset;
            while (n-- != 0) {
                if (v1[i++] != v2[j++])
                return false;
            }
            return true;
            }
        }
        return false;
        }

    java.lang.Object

    /**
         * Indicates whether some other object is "equal to" this one.
         * <p>
         * The <code>equals</code> method implements an equivalence relation
         * on non-null object references:
         * <ul>
         * <li>It is <i>reflexive</i>: for any non-null reference value
         *     <code>x</code>, <code>x.equals(x)</code> should return
         *     <code>true</code>.
         * <li>It is <i>symmetric</i>: for any non-null reference values
         *     <code>x</code> and <code>y</code>, <code>x.equals(y)</code>
         *     should return <code>true</code> if and only if
         *     <code>y.equals(x)</code> returns <code>true</code>.
         * <li>It is <i>transitive</i>: for any non-null reference values
         *     <code>x</code>, <code>y</code>, and <code>z</code>, if
         *     <code>x.equals(y)</code> returns <code>true</code> and
         *     <code>y.equals(z)</code> returns <code>true</code>, then
         *     <code>x.equals(z)</code> should return <code>true</code>.
         * <li>It is <i>consistent</i>: for any non-null reference values
         *     <code>x</code> and <code>y</code>, multiple invocations of
         *     <tt>x.equals(y)</tt> consistently return <code>true</code>
         *     or consistently return <code>false</code>, provided no
         *     information used in <code>equals</code> comparisons on the
         *     objects is modified.
         * <li>For any non-null reference value <code>x</code>,
         *     <code>x.equals(null)</code> should return <code>false</code>.
         * </ul>
         * <p>
         * The <tt>equals</tt> method for class <code>Object</code> implements 
         * the most discriminating possible equivalence relation on objects; 
         * that is, for any non-null reference values <code>x</code> and
         * <code>y</code>, this method returns <code>true</code> if and only
         * if <code>x</code> and <code>y</code> refer to the same object
         * (<code>x == y</code> has the value <code>true</code>).
         * <p>
         * Note that it is generally necessary to override the <tt>hashCode</tt>
         * method whenever this method is overridden, so as to maintain the
         * general contract for the <tt>hashCode</tt> method, which states
         * that equal objects must have equal hash codes. 
         *
         * @param   obj   the reference object with which to compare.
         * @return  <code>true</code> if this object is the same as the obj
         *          argument; <code>false</code> otherwise.
         * @see     #hashCode()
         * @see     java.util.Hashtable
         */
        public boolean equals(Object obj) {
        return (this == obj);
        }
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  • 原文地址:https://www.cnblogs.com/softidea/p/4558095.html
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