简单的数位dp
直接用dfs的模板写
坑点:0001是合法的,但是之前没考虑前导0导致将其判为不合法的
#include<bits/stdc++.h> using namespace std; typedef long long ll; int bit[50]; ll f[50][55]; ll dfs(int pos,int last, bool flag) { if(pos == 0) return 1; if(flag && f[pos][last] != -1) return f[pos][last]; ll ans = 0; int up = flag ? 9 : bit[pos]; for(int i = 0; i <= up; i++) { if(abs(i - last) < 2) continue; else{ if(last == 50 && i == 0) ans += dfs(pos-1, 50, flag || i < up); else ans += dfs(pos-1, i, flag || i < up); } } if(flag) f[pos][last] = ans; return ans; } ll solve(ll x) { int len = 0; while(x){ bit[++len] = x % 10; x /= 10; } return dfs(len,50,false); } int main() { int t; memset(f,-1,sizeof(f)); ll a;scanf("%lld",&a); ll b;scanf("%lld",&b); printf("%lld ",solve(b) - solve(a-1)); return 0; }