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  • 力扣——candy (分糖果) python实现

    题目描述:

    中文:

    老师想给孩子们分发糖果,有 N 个孩子站成了一条直线,老师会根据每个孩子的表现,预先给他们评分。

    你需要按照以下要求,帮助老师给这些孩子分发糖果:

    每个孩子至少分配到 1 个糖果。
    相邻的孩子中,评分高的孩子必须获得更多的糖果。

    那么这样下来,老师至少需要准备多少颗糖果呢?

    英文:

    There are N children standing in a line. Each child is assigned a rating value.

    You are giving candies to these children subjected to the following requirements:

    Each child must have at least one candy.
    Children with a higher rating get more candies than their neighbors.

    What is the minimum candies you must give?

    class Solution(object):
        def candy(self, ratings):
            """
            :type ratings: List[int]
            :rtype: int
            """
            s = 0
            n=len(ratings)
            s+=n
            tmp =[0]*n
            for i in range(1,n):
                if ratings[i]>ratings[i-1]:
                    tmp[i] = tmp[i-1]+1
            for i in range(n-2,-1,-1):
                if ratings[i]>ratings[i+1]:
                    tmp[i]=max(tmp[i],tmp[i+1]+1)
            s+=sum(tmp)
            return s

    题目来源:力扣

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  • 原文地址:https://www.cnblogs.com/spp666/p/11604551.html
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