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  • [Swift]LeetCode497. 非重叠矩形中的随机点 | Random Point in Non-overlapping Rectangles

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    Given a list of non-overlapping axis-aligned rectangles rects, write a function pick which randomly and uniformily picks an integer point in the space covered by the rectangles.

    Note:

    1. An integer point is a point that has integer coordinates. 
    2. A point on the perimeter of a rectangle is included in the space covered by the rectangles. 
    3. ith rectangle = rects[i][x1,y1,x2,y2], where [x1, y1] are the integer coordinates of the bottom-left corner, and [x2, y2] are the integer coordinates of the top-right corner.
    4. length and width of each rectangle does not exceed 2000.
    5. 1 <= rects.length <= 100
    6. pick return a point as an array of integer coordinates [p_x, p_y]
    7. pick is called at most 10000 times.

    Example 1:

    Input: 
    ["Solution","pick","pick","pick"]
    [[[[1,1,5,5]]],[],[],[]]
    Output: 
    [null,[4,1],[4,1],[3,3]]
    

    Example 2:

    Input: 
    ["Solution","pick","pick","pick","pick","pick"]
    [[[[-2,-2,-1,-1],[1,0,3,0]]],[],[],[],[],[]]
    Output: 
    [null,[-1,-2],[2,0],[-2,-1],[3,0],[-2,-2]]

    Explanation of Input Syntax:

    The input is two lists: the subroutines called and their arguments. Solution's constructor has one argument, the array of rectangles rectspick has no arguments. Arguments are always wrapped with a list, even if there aren't any.


    给定一个非重叠轴对齐矩形的列表 rects,写一个函数 pick 随机均匀地选取矩形覆盖的空间中的整数点。

    提示:

    1. 整数点是具有整数坐标的点。
    2. 矩形周边上的点包含在矩形覆盖的空间中。
    3. 第 i 个矩形 rects [i] = [x1,y1,x2,y2],其中 [x1,y1] 是左下角的整数坐标,[x2,y2] 是右上角的整数坐标。
    4. 每个矩形的长度和宽度不超过 2000。
    5. 1 <= rects.length <= 100
    6. pick 以整数坐标数组 [p_x, p_y] 的形式返回一个点。
    7. pick 最多被调用10000次。 

    示例 1:

    输入: 
    ["Solution","pick","pick","pick"]
    [[[[1,1,5,5]]],[],[],[]]
    输出: 
    [null,[4,1],[4,1],[3,3]]
    

    示例 2:

    输入: 
    ["Solution","pick","pick","pick","pick","pick"]
    [[[[-2,-2,-1,-1],[1,0,3,0]]],[],[],[],[],[]]
    输出: 
    [null,[-1,-2],[2,0],[-2,-1],[3,0],[-2,-2]] 

    输入语法的说明:

    输入是两个列表:调用的子例程及其参数。Solution的构造函数有一个参数,即矩形数组 rectspick没有参数。参数总是用列表包装的,即使没有也是如此。


    520ms
     1 class Solution {
     2 
     3     let rects : [[Int]]
     4     let w: [Int]
     5     let sum: Int
     6     
     7     init(_ rects: [[Int]]) {
     8         func area(_ a: [Int]) -> Int {
     9             return abs(a[2]-a[0]+1)*abs(a[3]-a[1]+1)
    10         }
    11         self.rects = rects
    12         w = rects.reduce(into: [Int]()) { $0.append(area($1)+($0.last ?? 0))}
    13         sum = rects.reduce(0) { $0+area($1) }
    14     }
    15         
    16     func pick() -> [Int] {
    17       let random = Int.random(in: 0...sum-1)
    18         let i = searchInsert(w, random)
    19       let r = rects[searchInsert(w, random)]
    20       return [Int.random(in: r[0]...r[2]), Int.random(in: r[1]...r[3])]
    21     }
    22     
    23     func searchInsert(_ nums: [Int], _ target: Int) -> Int {
    24         var low = 0
    25         var high = nums.count-1
    26         while low <= high {
    27             let middle = (low + high) / 2
    28             if nums[middle] == target {
    29                 return middle+1
    30             } else if nums[middle] > target {
    31                 high = middle - 1
    32             } else {
    33                 low = middle + 1
    34             }
    35         }
    36         return low
    37     }
    38 }
    39 
    40 /**
    41  * Your Solution object will be instantiated and called as such:
    42  * let obj = Solution(rects)
    43  * let ret_1: [Int] = obj.pick()
    44  */
    45  
    46 /**
    47  * Your Solution object will be instantiated and called as such:
    48  * let obj = Solution(rects)
    49  * let ret_1: [Int] = obj.pick()
    50  */

    Runtime: 844 ms
    Memory Usage: 22.3 MB
     1 class Solution {
     2     var _rects:[[Int]]
     3 
     4     init(_ rects: [[Int]]) {
     5         _rects = rects        
     6     }
     7     
     8     func pick() -> [Int] {
     9         var sumArea:Int = 0
    10         var selected:[Int] = [Int]()
    11         for rect in _rects
    12         {
    13             var area:Int = (rect[2] - rect[0] + 1) * (rect[3] - rect[1] + 1)
    14             sumArea += area
    15             if Int.random(in: 0..<sumArea) < area
    16             {
    17                 selected = rect
    18             }
    19         }
    20         var x:Int = Int.random(in: 0..<(selected[2] - selected[0] + 1)) + selected[0]
    21         var y:Int = Int.random(in: 0..<(selected[3] - selected[1] + 1)) + selected[1]
    22         return [x,y]      
    23     }
    24 }
    25 
    26 /**
    27  * Your Solution object will be instantiated and called as such:
    28  * let obj = Solution(rects)
    29  * let ret_1: [Int] = obj.pick()
    30  */
    31  
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  • 原文地址:https://www.cnblogs.com/strengthen/p/10391824.html
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