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  • [Swift]LeetCode867. 转置矩阵 | Transpose Matrix

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    Given a matrix A, return the transpose of A.

    The transpose of a matrix is the matrix flipped over it's main diagonal, switching the row and column indices of the matrix. 

    Example 1:

    Input: [[1,2,3],[4,5,6],[7,8,9]]
    Output: [[1,4,7],[2,5,8],[3,6,9]]
    

    Example 2:

    Input: [[1,2,3],[4,5,6]]
    Output: [[1,4],[2,5],[3,6]] 

    Note:

    1. 1 <= A.length <= 1000
    2. 1 <= A[0].length <= 1000

    给定一个矩阵 A, 返回 A 的转置矩阵。

    矩阵的转置是指将矩阵的主对角线翻转,交换矩阵的行索引与列索引。 

    示例 1:

    输入:[[1,2,3],[4,5,6],[7,8,9]]
    输出:[[1,4,7],[2,5,8],[3,6,9]]
    

    示例 2:

    输入:[[1,2,3],[4,5,6]]
    输出:[[1,4],[2,5],[3,6]] 

    提示:

    1. 1 <= A.length <= 1000
    2. 1 <= A[0].length <= 1000

    Runtime: 92 ms
    Memory Usage: 19 MB
     1 class Solution {
     2     func transpose(_ A: [[Int]]) -> [[Int]] {
     3         var tmp = Array(repeating: (Array(repeating:0, count: A.count)), count: A[0].count)
     4         for i in 0..<A[0].count {
     5             for j in 0..<A.count {
     6                 tmp[i][j] = A[j][i]
     7             }
     8         }
     9         
    10         return tmp
    11     }
    12 }

    Runtime: 92 ms
    Memory Usage: 19.2 MB
     1 class Solution {
     2     func transpose(_ A: [[Int]]) -> [[Int]] {
     3         if A.count == 0 {
     4             return []
     5         }
     6         let count = A[0].count
     7         var R: [[Int]] = []
     8         for j in 0..<count {
     9           var r: [Int] = []
    10             for i in 0..<A.count {
    11                 r.append(A[i][j])
    12             }
    13             R.append(r)
    14         }
    15         
    16         return R        
    17     }
    18 }

    116ms

     1 class Solution {
     2 func transpose(_ A: [[Int]]) -> [[Int]] {
     3     var result: [[Int]] = []
     4     for i in 0..<A[0].count {
     5         result.append([])
     6         for j in 0..<A.count {
     7             result[i].append(A[j][i])
     8         }
     9     }
    10     return result
    11   }
    12 }

    124ms

     1 class Solution {
     2     func transpose(_ A: [[Int]]) -> [[Int]] {
     3         var x = A.count
     4         var y = A[0].count
     5         var result: [[Int]] = []
     6         
     7         for i in 0..<y {
     8             var list: [Int] = []
     9             for j in 0..<x {
    10                 list += [A[j][i]]
    11             }
    12             result += [list]
    13         }
    14         
    15         return result        
    16     }
    17 }

    128ms

    class Solution {
        func transpose(_ A: [[Int]]) -> [[Int]] {
            
            var row = -1
            var column = -1
            let result = Array(count: A[0].count) { () -> [Int] in
                row += 1
                column = -1
                return Array(count: A.count) { () -> Int in
                    column += 1
                    return A[column][row]
                }
            } 
            return result
        }
    }
    
    public extension Array {
        public init(count: Int, generator: @escaping() -> Element) {
            precondition(count >= 0, "arrays must have non-negative size")
            self.init((0..<count).lazy.map { Element in generator() })
        }
    }
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  • 原文地址:https://www.cnblogs.com/strengthen/p/10588964.html
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